trunk/multipole/multipole1.tex

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\begin{document}

\preprint{AIP/123-QED}

\title[Taylor-shifted and Gradient-shifted electrostatics for multipoles]
{Real space alternatives to the Ewald
Sum. I. Taylor-shifted and Gradient-shifted electrostatics for multipoles}

\author{Madan Lamichhane}
\affiliation{Department of Physics, University
of Notre Dame, Notre Dame, IN 46556}

\author{J. Daniel Gezelter}
 \email{gezelter@nd.edu.}
\affiliation{Department of Chemistry and Biochemistry, University
of Notre Dame, Notre Dame, IN 46556}

\author{Kathie E. Newman}
\affiliation{Department of Physics, University
of Notre Dame, Notre Dame, IN 46556}


\date{\today}% It is always \today, today,
             %  but any date may be explicitly specified

\begin{abstract}
  We have extended the original damped-shifted force (DSF)
  electrostatic kernel and have been able to derive two new
  electrostatic potentials for higher-order multipoles that are based
  on truncated Taylor expansions around the cutoff radius.  For
  multipole-multipole interactions, we find that each of the distinct
  orientational contributions has a separate radial function to ensure
  that the overall forces and torques vanish at the cutoff radius. In
  this paper, we present energy, force, and torque expressions for the
  new models, and compare these real-space interaction models to exact
  results for ordered arrays of multipoles.
\end{abstract}

\pacs{Valid PACS appear here}% PACS, the Physics and Astronomy
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\keywords{Suggested keywords}%Use showkeys class option if keyword
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\maketitle

\section{Introduction}

There is increasing interest in real-space methods for calculating
electrostatic interactions in computer simulations of condensed
molecular
systems.\cite{Wolf99,Zahn02,Kast03,BeckD.A.C._bi0486381,Ma05,Fennell:2006zl,Chen:2004du,Chen:2006ii,Rodgers:2006nw,Denesyuk:2008ez,Izvekov:2008wo}
The simplest of these techniques was developed by Wolf {\it et al.}
in their work towards an $\mathcal{O}(N)$ Coulombic sum.\cite{Wolf99}
Fennell and Gezelter showed that a simple damped shifted force (DSF)
modification to Wolf's method could give nearly quantitative agreement
with smooth particle mesh Ewald (SPME)\cite{Essmann95} for quantities
of interest in Monte Carlo (i.e., configurational energy differences)
and Molecular Dynamics (i.e., atomic force and molecular torque
vectors).\cite{Fennell:2006zl}

The computational efficiency and the accuracy of the DSF method are
surprisingly good, particularly for systems with uniform charge
density. Additionally, dielectric constants obtained using DSF and
similar methods where the force vanishes at $R_\textrm{c}$ are
essentially quantitative.\cite{Izvekov:2008wo} The DSF and other
related methods have now been widely investigated,\cite{Hansen:2012uq}
and DSF is now used routinely in simulations of ionic
liquids,\cite{doi:10.1021/la400226g,McCann:2013fk} flow in carbon
nanotubes,\cite{kannam:094701} gas sorption in metal-organic framework
materials,\cite{Forrest:2012ly} thermal conductivity of methane
hydrates,\cite{English:2008kx} condensation coefficients of
water,\cite{Louden:2013ve} and in tribology at solid-liquid-solid
interfaces.\cite{Tokumasu:2013zr} DSF electrostatics provides a
compromise between the computational speed of real-space cutoffs and
the accuracy of fully-periodic Ewald treatments.

One common feature of many coarse-graining approaches, which treat
entire molecular subsystems as a single rigid body, is simplification
of the electrostatic interactions between these bodies so that fewer
site-site interactions are required to compute configurational
energies. Notably, the force matching approaches of Voth and coworkers
are an exciting development in their ability to represent realistic
(and {\it reactive}) chemical systems for very large length scales and
long times.  This approach utilized a coarse-graining in interaction
space (CGIS) which fits an effective force for the coarse grained
system using a variational force-matching method to a fine-grained
simulation.\cite{Izvekov:2008wo}

The coarse-graining approaches of Ren \& coworkers,\cite{Golubkov06}
and Essex \&
coworkers,\cite{ISI:000276097500009,ISI:000298664400012}
both utilize Gay-Berne
ellipsoids~\cite{Berne72,Gay81,Luckhurst90,Cleaver96,Berardi98,Ravichandran:1999fk,Berardi99,Pasterny00}
to model dispersive interactions and point multipoles to model
electrostatics for entire molecules or functional groups.

Ichiye and coworkers have recently introduced a number of very fast
water models based on a ``sticky'' multipole model which are
qualitatively better at reproducing the behavior of real water than
the more common point-charge models (SPC/E, TIPnP).  The point charge
models are also substantially more computationally demanding than the
sticky multipole
approach.\cite{Chowdhuri:2006lr,Te:2010rt,Te:2010ys,Te:2010vn} The
SSDQO model requires the use of an approximate multipole expansion
(AME) as the exact multipole expansion is quite expensive
(particularly when handled via the Ewald sum).\cite{Ichiye:2006qy}
Another particularly important use of point multipoles (and multipole
polarizability) is in the very high-quality AMOEBA water model and
related force fields.\cite{Ponder:2010fk,schnieders:124114,Ren:2011uq}

Higher-order multipoles present a peculiar issue for molecular
dynamics. Multipolar interactions are inherently short-ranged, and
should not need the relatively expensive Ewald treatment.  However,
real-space cutoff methods are normally applied in an orientation-blind
fashion so multipoles which leave and then re-enter a cutoff sphere in
a different orientation can cause energy discontinuities.

This paper outlines an extension of the original DSF electrostatic
kernel to point multipoles.  We present in this paper two distinct
real-space interaction models for higher-order multipoles based on two
truncated Taylor expansions that are carried out at the cutoff radius.
We are calling these models {\bf Taylor-shifted} and {\bf
  Gradient-shifted} electrostatics.  Because of differences in the
initial assumptions, the two methods yield related, but different
expressions for energies, forces, and torques.

\section{Methodology}

\subsection{Self-neutralization, damping, and force-shifting}

The DSF and Wolf methods operate by neutralizing the total charge
contained within the cutoff sphere surrounding each particle.  This is
accomplished by shifting the potential functions to generate image
charges on the surface of the cutoff sphere for each pair interaction
computed within $R_\textrm{c}$. An Ewald-like complementary error
function damping is applied to the potential to accelerate
convergence.  The potential for the DSF method, where $\alpha$ is the
adjustable damping parameter, is given by
\begin{equation*}
V_\mathrm{DSF}(r) = C_a C_b \Biggr{[}
\frac{\mathrm{erfc}\left(\alpha r_{ij}\right)}{r_{ij}} 
- \frac{\mathrm{erfc}\left(\alpha R_\mathrm{c}\right)}{R_\mathrm{c}} + \left(\frac{\mathrm{erfc}\left(\alpha R_\mathrm{c}\right)}{R_\mathrm{c}^2} 
+ \frac{2\alpha}{\pi^{1/2}}
\frac{\exp\left(-\alpha^2R_\mathrm{c}^2\right)}{R_\mathrm{c}}
\right)\left(r_{ij}-R_\mathrm{c}\right)\ \Biggr{]} 
\label{eq:DSFPot}
\end{equation*}

To insure net charge neutrality within each cutoff sphere, an
additional ``self'' term is added to the potential. This term is
constant (as long as the charges and cutoff radius do not change), and
exists outside the normal pair-loop for molecular simulations.  It can
be thought of as a contribution from a charge opposite in sign, but
equal in magnitude, to the central charge, which has been spread out
over the surface of the cutoff sphere.  A portion of the self term is
identical to the self term in the Ewald summation, and comes from the
utilization of the complimentary error function for electrostatic
damping.\cite{deLeeuw80,Wolf99}

\begin{figure}
\includegraphics[width=\linewidth]{SM}
\caption{Reversed multipoles are projected onto the surface of the
  cutoff sphere. The forces, torques, and potential are then smoothly
  shifted to zero as the sites leave the cutoff region.}
\label{fig:shiftedMultipoles}
\end{figure}

\subsection{Multipole Expansion}

Consider two discrete rigid collections of point charges, denoted as
objects $\bf a$ and $\bf b$.  In the following, we assume that the two
objects only interact via electrostatics and describe those
interactions in terms of a multipole expansion.  Putting the origin of
the coordinate system at the center of mass of $\bf a$, we use vectors
$\mathbf{r}_k$ to denote the positions of all charges $q_k$ in $\bf
a$.  Then the electrostatic potential of object $\bf a$ at
$\mathbf{r}$ is given by
\begin{equation}
V_a(\mathbf r) = \frac{1}{4\pi\epsilon_0}
 \sum_{k \, \text{in \bf a}} \frac{q_k}{\lvert \mathbf{r} - \mathbf{r}_k \rvert}.
\end{equation}
We write the Taylor series expansion in $r$ using an implied summation
notation, Greek indices are used to indicate space coordinates ($x$,
$y$, $z$) and the subscripts $k$ and $j$ are reserved for labelling
specific charges in $\bf a$ and $\bf b$ respectively, and find:
\begin{equation}
 \frac{1}{\lvert \mathbf{r} - \mathbf{r}_k \rvert} = 
\left( 1
-  r_{k\alpha} \frac{\partial}{\partial r_{\alpha}} 
+ \frac{1}{2}  r_{k\alpha} r_{k\beta} \frac{\partial^2}{\partial r_{\alpha} \partial r_{\beta}} +\dots 
\right)
\frac{1}{r}  .
\end{equation}
The electrostatic potential on $\bf a$ can then be expressed in terms
of multipole operators,
\begin{equation}
V_{\bf a}(\mathbf{r}) = \frac{1}{4\pi\epsilon_0}\hat{M}_{\bf a} \frac{1}{r} 
\end{equation}
where
\begin{equation}
\hat{M}_{\bf a} = C_{\bf a} - D_{{\bf a}\alpha} \frac{\partial}{\partial r_{\alpha}} 
+  Q_{{\bf a}\alpha\beta}
 \frac{\partial^2}{\partial r_{\alpha} \partial r_{\beta}} + \dots
\end{equation}
Here, the point charge, dipole, and quadrupole for object $\bf a$ are
given by $C_{\bf a}$, $D_{{\bf a}\alpha}$, and $Q_{{\bf
    a}\alpha\beta}$, respectively.  These can be tied to distribution
of charges
\begin{equation}
C_{\bf a}=\sum_{k \, \text{in \bf a}} q_k ,
\end{equation}
\begin{equation}
D_{{\bf a}\alpha} = \sum_{k \, \text{in \bf a}} q_k r_{k\alpha} ,
\end{equation}
\begin{equation}
Q_{{\bf a}\alpha\beta} = \frac{1}{2} \sum_{k \, \text{in \bf a}} q_k r_{k\alpha}  r_{k\beta} .
\end{equation}

It is convenient to locate charges $q_j$ relative to the center of mass of  $\bf b$.  Then with $\bf{r}$ pointing from
$\bf a$ to $\bf b$ ($\mathbf{r}=\mathbf{r}_b - \mathbf{r}_b $), the interaction energy is given by
\begin{eqnarray}
U_{\bf{ab}}(r) =&& \frac{1}{4\pi \epsilon_0}
\sum_{k \, \text{in \bf a}} \sum_{j \, \text{in \bf b}}
\frac{q_k q_j}{\vert \bf{r}_k - (\bf{r}+\bf{r}_j) \vert} \nonumber\\
=&& \frac{1}{4\pi \epsilon_0}
\sum_{k \, \text{in \bf a}} \sum_{j \, \text{in \bf b}}
\frac{q_k q_j}{\vert \bf{r}+ (\bf{r}_j-\bf{r}_k) \vert} \nonumber\\
=&&\frac{1}{4\pi \epsilon_0}  \sum_{j \, \text{in \bf b}}  q_j V_a(\bf{r}+\bf{r}_j) \nonumber\\
=&&\frac{1}{4\pi \epsilon_0} \hat{M}_a \sum_{j \, \text{in \bf b}} \frac {q_j}{\vert \bf{r}+\bf{r}_j \vert} .
\end{eqnarray}
The last expression can also be expanded as a Taylor series in $r$.  Using a notation similar to before, we define
\begin{equation}
\hat{M}_{\bf b} = C_{\bf b} + D_{{\bf b}\alpha} \frac{\partial}{\partial r_{\alpha}} 
+   Q_{{\bf b}\alpha\beta}
 \frac{\partial^2}{\partial r_{\alpha} \partial r_{\beta}} + \dots
\end{equation}
and
\begin{equation}
U_{\bf{ab}}(r)=\frac{\hat{M}_{\bf a} \hat{M}_{\bf b}}{4\pi \epsilon_0} \frac{1}{r}  \label{kernel}.
\end{equation}
Note the ease of separting out the respective energies of interaction of the charge, dipole, and quadrupole of $\bf a$  from those of $\bf b$.

\subsection{Bare Coulomb versus smeared charge}

With the four types of methods being considered here, it is desirable to list the approximations in as transparent a form
as possible.  First, one may use the bare Coulomb potential, with radial dependence $1/r$, 
as shown in Eq.~(\ref{kernel}).  Alternatively, one may use
a smeared charge distribution, then the``kernel'' $1/r$ of the expansion is replaced with a function:
\begin{equation}
B_0(r)=\frac{\text{erfc}(\alpha r)}{r} = \frac{2}{\sqrt{\pi}r}
\int_{\alpha r}^{\infty} \text{e}^{-s^2} ds .
\end{equation}
We develop equations using a function $f(r)$ to represent either $1/r$ or $B_0(r)$, dependent on the the type of approach being considered.
Smith's convenient functions $B_l(r)$ are summarized in Appendix A.

\subsection{Shifting the force, method 1}

As discussed in the introduction, it is desirable to cutoff the electrostatic energy at a radius
$r_c$.  For consistency in approximation, we want the interaction energy as well as the force and
torque to go to zero at $r=r_c$.  
To describe how this goal may be met using a radial approximation, we use two examples, charge-charge
and charge-dipole, using the bare Coulomb kernel $f(r)=1/r$ to explain the idea.

In the shifted-force approximation, the interaction energy $U_{\bf{ab}}(r_c)=0$ 
for two charges $C_{\bf a}$ and $C_{\bf b}$ separated by a distance $r$ is written:
\begin{equation}
U_{C_{\bf a}C_{\bf b}}(r)=\frac{1}{4\pi \epsilon_0} C_{\bf a} C_{\bf b}
\left({ \frac{1}{r} - \frac{1}{r_c} + (r - r_c) \frac{1}{r_c^2}  }
\right) .
\end{equation}
Two shifting terms appear in this equations because we want the force to
also be shifted due to an image charge located at a distance $r_c$.  
Since one derivative of the interaction energy is needed for the force, we want a term
linear in $(r-r_c)$ in the interaction energy, that is:
\begin{equation}
\frac{d\,}{dr} 
\left( {\frac{1}{r} - \frac{1}{r_c} + (r - r_c) \frac{1}{r_c^2}  }
\right) = \left(- \frac{1}{r^2} + \frac{1}{r_c^2} 
\right) .
\end{equation}
This demonstrates the need of the third term in the brackets of the energy expression, but  leads to the question, how does this idea generalize for higher-order multipole energies?

In method 1, the procedure that we follow is based on the number of derivatives need for each energy, force, or torque.  That is,
a quadrupole-quadrupole interaction energy will have four derivatives,
$\partial^4/\partial r_\alpha \partial r_\beta \partial r_\gamma \partial r_\delta$,
and the force or torque will bring in yet another derivative.  
We thus want shifted energy expressions to include terms so that all energies, forces, and torques
are zero at $r=r_c$.  In each case, we will subtract off a function $f_n^{\text{shift}}(r)$ from the
kernel $f(r)=1/r$.  The index $n$ indicates the number of derivatives to be taken when
deriving a given multipole energy.
We choose a function with guaranteed smooth derivatives --- a truncated Taylor series of the function
$f(r)$, e.g., 
%
\begin{equation}
f_n^{\text{shift}}(r)=\sum_{m=0}^{n+1} \frac {(r-r_c)^m}{m!} f^{(m)} \Big \lvert  _{r_c}  .
\end{equation}
%
The combination of $f(r)$ with the shifted function is denoted $f_n(r)=f(r)-f_n^{\text{shift}}(r)$.
Thus, for $f(r)=1/r$, we find
%
\begin{equation}
f_1(r)=\frac{1}{r}- \frac{1}{r_c} + (r - r_c) \frac{1}{r_c^2} - \frac{(r-r_c)^2}{r_c^3} .
\end{equation}
%
Continuing with the example of a charge  $\bf a$  interacting with a dipole  $\bf b$, we write
%
\begin{equation}
U_{C_{\bf a}D_{\bf b}}(r)=
\frac{C_{\bf a} D_{{\bf b}\alpha}}{4\pi \epsilon_0}  \frac {\partial f_1(r) }{\partial r_\alpha} 
=\frac{ C_{\bf a} D_{{\bf b}\alpha}}{4\pi \epsilon_0}   
\frac {r_\alpha}{r} \frac {\partial f_1(r)}{\partial r} .
\end{equation}
%
The force that dipole  $\bf b$ puts on charge $\bf a$ is
%
\begin{equation}
F_{C_{\bf a}D_{\bf b}\beta} =\frac{ C_{\bf a} D_{{\bf b}\alpha}}{4\pi \epsilon_0}
\left[ \frac{\delta_{\alpha\beta}}{r} \frac {\partial}{\partial r} + 
\frac{r_\alpha r_\beta}{r^2}
\left( -\frac{1}{r} \frac {\partial} {\partial r} 
+ \frac {\partial ^2} {\partial r^2} \right) \right] f_1(r) .
\end{equation}
%
For $f(r)=1/r$, we find
%
\begin{equation}
F_{C_{\bf a}D_{\bf b}\beta} =
\frac{C_{\bf a} D_{{\bf b}\beta} }{4\pi \epsilon_0r}
\left[  -\frac{1}{r^2}+\frac{1}{r_c^2}-\frac{2(r-r_c)}{r_c^3} \right] 
+\frac{C_{\bf a} D_{{\bf b}\alpha}r_\alpha r_\beta }{4\pi \epsilon_0}
\left[ \frac{3}{r^5}-\frac{3}{r^3r_c^2} \right] .
\end{equation}
%
This expansion shows the expected $1/r^3$ dependence of the force.  

In general, we write
%
\begin{equation}
U=\frac{1}{4\pi \epsilon_0} (\text{prefactor}) (\text{derivatives}) f_n(r)
\label{generic}
\end{equation}
%
where $n=0$ for charge-charge, $n=1$ for charge-dipole, $n=2$ for charge-quadrupole
and dipole-dipole, $n=3$ for dipole-quadrupole, and $n=4$ for quadrupole-quadrupole.
An example is the case of quadrupole-quadrupole for which the $\text{prefactor}$ is 
$Q_{{\bf a}\alpha\beta}Q_{{\bf b}\gamma\delta}$ and the derivatives are
$\partial^4/\partial r_\alpha \partial r_\beta \partial r_\gamma \partial r_\delta$, with
implied summation combining the space indices.

To apply this method  to the smeared-charge approach,  
we write $f(r)=\text{erfc}(\alpha r)/r$.  By using one function $f(r)$ for both
approaches, we simplify the tabulation of equations used.  Because
of the many derivatives that are taken, the algebra is tedious and are summarized
in Appendices A and B.  

\subsection{Shifting the force, method 2}

Note the method used in the previous subsection to shift a force is basically that of using
a truncated Taylor Series in the radius $r$.  An alternate method exists, best explained by
writing one shifted formula for all interaction energies $U(r)$:
\begin{equation}
U^{\text{shift}}(r)=U(r)-U(r_c)-(r-r_c)\hat{r}\cdot \nabla U(r) \Big \lvert  _{r_c} .
\end{equation}
Note that this method uses only the linear term, $(r-r_c)$ in the Taylor series, no higher order terms
$(r-r_c)^n$ appear.   The primary difference between methods 1 and 2 originates
with the stage in the derivation where the Taylor Series is applied; in method 1, it is applied to the 
kernel.  In method 2, it is applied to individual interaction energies of the multipole expansion.
Terms from this method thus have the general form:
\begin{equation}
U=\frac{1}{4\pi \epsilon_0}\sum  (\text{angular factor}) (\text{radial factor}).
\label{generic2}
\end{equation}

Results for both methods can be summarized using the form of Eq.~(\ref{generic2})
and are listed in Table I below.

\subsection{\label{sec:level2}Body and space axes}

Up to this point, all energies and forces have been written in terms of fixed space
coordinates $x$, $y$, $z$.  Interaction energies are computed from the generic formulas Eq.~(\ref{generic}) and ~(\ref{generic2}) which 
combine prefactors with radial functions.  But because objects
 $\bf a$ and  $\bf b$ both translate and rotate as part of a MD simulation,
it is desirable to contract all $r$-dependent terms with dipole and quadrupole
moments expressed in terms of their body axes.  
Since the interaction energy expressions will be used to derive both forces and torques,
we follow here the development of Allen and Germano, which was itself based on an 
earlier paper by Price \em et al.\em

Denote body axes for objects  $\bf a$ and  $\bf b$ by unit vectors
$\hat{a}_m$ and $\hat{b}_m$, respectively, with the index $m=(123)$ referring to a convenient
set of inertial body axes.  (Note, these body axes are generally not the same as those for which the
quadrupole moment is diagonal.)  Then,
%
\begin{eqnarray}
\hat{a}_m= a_{mx}\hat{x} + a_{my}\hat{y} + a_{mz}\hat{z}  \\
\hat{b}_m= b_{mx}\hat{x} + b_{my}\hat{y} + b_{mz}\hat{z}  .
\end{eqnarray}
Allen and Germano define matrices $\hat{\mathbf {a}}$ 
and  $\hat{\mathbf {b}}$ using these unit vectors:
\begin{eqnarray}
\hat{\mathbf {a}} = 
\begin{pmatrix}
\hat{a}_1 \\
\hat{a}_2 \\
\hat{a}_3
\end{pmatrix}
=
\begin{pmatrix}
a_{1x} \quad a_{1y} \quad a_{1z} \\
a_{2x} \quad a_{2y} \quad a_{2z} \\
a_{3x} \quad a_{3y} \quad a_{3z}
\end{pmatrix}\\
\hat{\mathbf {b}} = 
\begin{pmatrix}
\hat{b}_1 \\
\hat{b}_2 \\
\hat{b}_3
\end{pmatrix}
=
\begin{pmatrix}
b_{1x}\quad  b_{1y} \quad b_{1z} \\
b_{2x} \quad b_{2y} \quad b_{2z} \\
b_{3x} \quad b_{3y} \quad b_{3z}
\end{pmatrix}  .
\end{eqnarray}
%
These matrices convert from space-fixed $(xyz)$ to object-fixed $(123)$ coordinates.
All contractions of prefactors with derivatives of functions can be written in terms of these matrices.
It proves to be equally convenient to just write any contraction in terms of unit vectors
$\hat{r}$, $\hat{a}_m$, and $\hat{b}_n$.  
We have found it useful to write angular-dependent terms in three different fashions,
illustrated by the following 
three examples from the interaction-energy expressions:
%
\begin{eqnarray}
 \mathbf{D}_{\mathbf {a}} \cdot \mathbf{D}_{\mathbf{b}}
=D_{\bf {a}\alpha} D_{\bf {b}\alpha}=
\sum_{mn} {D_{\mathbf{a}m} \hat{a}_m \cdot \hat{b}_n D_{\mathbf{b}n}} \\
r^2 \left( \hat{r} \cdot  \mathbf{Q}_{{\mathbf b}} \cdot \hat{r} \right)=
r_\alpha Q_{\bf b \alpha \beta} r_\beta = r^2
\sum_{mn}(\hat{r} \cdot \hat{b}_m)  Q_{\mathbf{b}mn} (\hat{b}_n \cdot \hat{r}) \\
r ( \mathbf{D}_{\mathbf{a}} \cdot 
\mathbf{Q}_{\mathbf{b}}  \cdot \hat{r})=
D_{\bf {a}\alpha}  Q_{\bf b \alpha \beta} r_\beta
=r \sum_{lmn} D_{\mathbf{a}l} (\hat{a}_l \cdot \hat{b}_m ) Q_{\mathbf{b}mn}
(\hat{b}_n \cdot \hat{r}) .
\end{eqnarray}
%
[Dan, perhaps there are better examples to show here.]

In each line, the first two terms are written using space coordinates.  The first form is standard
in the chemistry literature, and the second is ``physicist style'' using implied summation notation.  The third 
form shows explicitly sums over body indices and the dot products now indicate contractions using space indices.
We find the first form to be useful in writing equations prior to converting to computer code.  The second form is helpful
in derivations of the interaction energy expressions.  The third one is specifically helpful when deriving forces and torques, as will
be discussed below.  


\section{The Self-Interaction}
The Wolf summation~\cite{Wolf99} and the later damped shifted force
(DSF) extension~\cite{Fennell06} included self-interactions that are
handled separately from the pairwise interactions between sites. The
self-term is normally calculated via a single loop over all sites in
the system, and is relatively cheap to evaluate. The self-interaction
has contributions from two sources:
\begin{itemize}
\item The neutralization procedure within the cutoff radius requires a
  contribution from a charge opposite in sign, but equal in magnitude,
  to the central charge, which has been spread out over the surface of
  the cutoff sphere.  For a system of undamped charges, the total
  self-term is
\begin{equation}
V_\textrm{self} = - \frac{1}{r_c} \sum_{{\bf a}=1}^N C_{\bf a}^{2}
\label{eq:selfTerm}
\end{equation}
Note that in this potential and in all electrostatic quantities that
follow, the standard $4 \pi \epsilon_{0}$ has been omitted for
clarity.
\item Charge damping with the complementary error function is a
  partial analogy to the Ewald procedure which splits the interaction
  into real and reciprocal space sums.  The real space sum is retained
  in the Wolf and DSF methods.  The reciprocal space sum is first
  minimized by folding the largest contribution (the self-interaction)
  into the self-interaction from charge neutralization of the damped
  potential.  The remainder of the reciprocal space portion is then
  discarded (as this contributes the largest computational cost and
  complexity to the Ewald sum).  For a system containing only damped
  charges, the complete self-interaction can be written as
\begin{equation}
V_\textrm{self} = - \left(\frac{\textrm{erfc}(\alpha r_c)}{r_c} + 
  \frac{\alpha}{\sqrt{\pi}} \right) \sum_{{\bf a}=1}^N
      C_{\bf a}^{2}.
\label{eq:dampSelfTerm}
\end{equation}
\end{itemize}

The extension of DSF electrostatics to point multipoles requires
treatment of {\it both} the self-neutralization and reciprocal
contributions to the self-interaction for higher order multipoles.  In
this section we give formulae for these interactions up to quadrupolar
order.

The self-neutralization term is computed by taking the {\it
  non-shifted} kernel for each interaction, placing a multipole of
equal magnitude (but opposite in polarization) on the surface of the
cutoff sphere, and averaging over the surface of the cutoff sphere.
Because the self term is carried out as a single sum over sites, the
reciprocal-space portion is identical to half of the self-term
obtained by Smith and Aguado and Madden for the application of the
Ewald sum to multipoles.\cite{Smith82,Smith98,Aguado03} For a given
site which posesses a charge, dipole, and multipole, both types of
contribution are given in table \ref{tab:tableSelf}.

\begin{table*}
  \caption{\label{tab:tableSelf} Self-interaction contributions for 
    site ({\bf a}) that has a charge $(C_{\bf a})$, dipole
    $(\mathbf{D}_{\bf a})$, and quadrupole $(\mathbf{Q}_{\bf a})$}
\begin{ruledtabular}
\begin{tabular}{lccc}
Multipole order & Summed Quantity & Self-neutralization  & Reciprocal \\ \hline
Charge & $C_{\bf a}^2$ & $-f(r_c)$ & $-\frac{\alpha}{\sqrt{\pi}}$ \\
Dipole & $|\mathbf{D}_{\bf a}|^2$ & $\frac{1}{3} \left( h(r_c) +
  \frac{2 g(r_c)}{r_c} \right)$ & $-\frac{2 \alpha^3}{3 \sqrt{\pi}}$\\
Quadrupole & $2 \text{Tr}(\mathbf{Q}_{\bf a}^2) + \text{Tr}(\mathbf{Q}_{\bf a})^2$ &
$- \frac{1}{15} \left( t(r_c)+ \frac{4 s(r_c)}{r_c} \right)$ &
$-\frac{4 \alpha^5}{5 \sqrt{\pi}}$ \\
Charge-Quadrupole & $-2 C_{\bf a} \text{Tr}(\mathbf{Q}_{\bf a})$ & $\frac{1}{3} \left(
  h(r_c) + \frac{2 g(r_c)}{r_c} \right)$& $-\frac{2 \alpha^3}{3 \sqrt{\pi}}$ \\
\end{tabular}
\end{ruledtabular}
\end{table*}

For sites which simultaneously contain charges and quadrupoles, the
self-interaction includes a cross-interaction between these two
multipole orders.  Symmetry prevents the charge-dipole and
dipole-quadrupole interactions from contributing to the
self-interaction.  The functions that go into the self-neutralization
terms, $f(r), g(r), h(r), s(r), \mathrm{~and~} t(r)$ are successive
derivatives of the electrostatic kernel (either the undamped $1/r$ or
the damped $B_0(r)=\mathrm{erfc}(\alpha r)/r$ function) that are
evaluated at the cutoff distance.  For undamped interactions, $f(r_c)
= 1/r_c$, $g(r_c) = -1/r_c^{2}$, and so on.  For damped interactions,
$f(r_c) = B_0(r_c)$, $g(r_c) = B_0'(r_c)$, and so on.  Appendix XX
contains recursion relations that allow rapid evaluation of these
derivatives.

\section{Energies, forces, and torques}
\subsection{Interaction energies}

We now list multipole interaction energies for the four types of approximation.  
A ``generic'' set of radial functions is introduced so to be able to present the results in Table I.  This set of
equations is written in terms of space coordinates:

% Energy in space coordinate form ----------------------------------------------------------------------------------------------
%
%
% u ca cb
%
\begin{equation}
U_{C_{\bf a}C_{\bf b}}(r)=
\frac{C_{\bf a} C_{\bf b}}{4\pi \epsilon_0}  v_{01}(r)  \label{uchch}
\end{equation}
%
% u ca db
%
\begin{equation}
U_{C_{\bf a}D_{\bf b}}(r)=
\frac{C_{\bf a}}{4\pi \epsilon_0} \left( \mathbf{D}_{\mathbf{b}} \cdot \hat{r} \right)  v_{11}(r)  
 \label{uchdip}
\end{equation}
%
% u ca qb
%
\begin{equation}
U_{C_{\bf a}Q_{\bf b}}(r)=
\frac{C_{\bf a }}{4\pi \epsilon_0} \Bigl[ \text{Tr}Q_{\bf b} v_{21}(r) 
\left( \hat{r} \cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r} \right) v_{22}(r) \Bigr]
\label{uchquad}
\end{equation}
%
% u da cb
%
\begin{equation}
U_{D_{\bf a}C_{\bf b}}(r)=
-\frac{C_{\bf b}}{4\pi \epsilon_0}  
\left( \mathbf{D}_{\mathbf{a}} \cdot \hat{r} \right)   v_{11}(r) \label{udipch}
\end{equation}
%
% u da db
%
\begin{equation}
U_{D_{\bf a}D_{\bf b}}(r)=
-\frac{1}{4\pi \epsilon_0} \Bigr[ \left( \mathbf{D}_{\mathbf {a}} \cdot
\mathbf{D}_{\mathbf{b}} \right)  v_{21}(r)
+\left( \mathbf{D}_{\mathbf {a}} \cdot \hat{r} \right)
\left( \mathbf{D}_{\mathbf {b}} \cdot \hat{r} \right)  
v_{22}(r) \Bigr]
\label{udipdip}
\end{equation}
%
% u da qb
%
\begin{equation}
\begin{split}
% 1
U_{D_{\bf a}Q_{\bf b}}(r)&=
-\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{b}}
\left( \mathbf{D}_{\mathbf{a}} \cdot \hat{r} \right)
+2 ( \mathbf{D}_{\mathbf{a}} \cdot
\mathbf{Q}_{\mathbf{b}} \cdot \hat{r} ) \Bigr] v_{31}(r) \\
% 2
&-\frac{1}{4\pi \epsilon_0} \left( \mathbf{D}_{\mathbf{a}} \cdot \hat{r} \right)
 \left( \hat{r} \cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r} \right) v_{32}(r)
\label{udipquad}
\end{split}
\end{equation}
%
% u qa cb
%
\begin{equation}
U_{Q_{\bf a}C_{\bf b}}(r)=
\frac{C_{\bf b }}{4\pi \epsilon_0} \Bigl[ \text{Tr}\mathbf{Q}_{\bf a}  v_{21}(r)
\left( \hat{r} \cdot \mathbf{Q}_{{\mathbf a}} \cdot \hat{r} \right)  v_{22}(r)  \Bigr]
\label{uquadch}
\end{equation}
%
% u qa db
%
\begin{equation}
\begin{split}
%1
U_{Q_{\bf a}D_{\bf b}}(r)&=
\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{a}}
\left(  \mathbf{D}_{\mathbf{b}} \cdot \hat{r} \right)
+2 ( \mathbf{D}_{\mathbf{b}} \cdot 
\mathbf{Q}_{\mathbf{a}}  \cdot \hat{r}) \Bigr] v_{31}(r)
% 2
+\frac{1}{4\pi \epsilon_0}
\left(  \mathbf{D}_{\mathbf{b}} \cdot \hat{r} \right)
\left( \hat{r} \cdot \mathbf{Q}_{{\mathbf a}} \cdot \hat{r} \right) v_{32}(r)
\label{uquaddip}
\end{split}
\end{equation}
%
% u qa qb
%
\begin{equation}
\begin{split}
%1
U_{Q_{\bf a}Q_{\bf b}}(r)&=
\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr} \mathbf{Q}_{\mathbf{a}} \text{Tr} \mathbf{Q}_{\mathbf{b}}
+2 \text{Tr} \left(
\mathbf{Q}_{\mathbf{a}} \cdot \mathbf{Q}_{\mathbf{b}} \right) \Bigr] v_{41}(r)
\\
% 2
&+ \frac{1}{4\pi \epsilon_0} \Bigl[ \text{Tr}\mathbf{Q}_{\mathbf{a}}
 \left( \hat{r} \cdot 
\mathbf{Q}_{{\mathbf b}} \cdot \hat{r} \right)
+\text{Tr}\mathbf{Q}_{\mathbf{b}}
\left( \hat{r} \cdot \mathbf{Q}_{{\mathbf a}}
 \cdot \hat{r} \right)  +4 (\hat{r}  \cdot
\mathbf{Q}_{{\mathbf a}}\cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r})
\Bigr] v_{42}(r)
 \\
% 4
&+ \frac{1}{4\pi \epsilon_0}
\left( \hat{r} \cdot  \mathbf{Q}_{{\mathbf a}} \cdot \hat{r} \right)
\left( \hat{r} \cdot \mathbf{Q}_{{\mathbf b}}  \cdot \hat{r} \right) v_{43}(r).
\label{uquadquad}
\end{split}
\end{equation}


%
%
% TABLE of radial functions  ----------------------------------------------------------------------------------------------------------------
%

\begin{table*}
\caption{\label{tab:tableenergy}Radial functions used in the energy and torque equations.  Functions
used in this table are defined in Appendices B and C.}
\begin{ruledtabular}
\begin{tabular}{cccc}
Generic&Coulomb&Method 1&Method 2
\\ \hline
%
%
%
%Ch-Ch&
$v_{01}(r)$ &
$\frac{1}{r}$ &
$f_0(r)$ &
$f(r)-f(r_c)-(r-r_c)g(r_c)$
\\
%
%
%
%Ch-Di&
$v_{11}(r)$ &
$-\frac{1}{r^2}$ &
$g_1(r)$ &
$g(r)-g(r_c)-(r-r_c)h(r_c)$ \\
%
%
%
%Ch-Qu/Di-Di&
$v_{21}(r)$ &
$-\frac{1}{r^3}  $ & 
$\frac{g_2(r)}{r} $ &
$\frac{g(r)}{r}-\frac{g(r_c)}{r_c} -(r-r_c)
\left( -\frac{g(r_c)}{r_c^2} + \frac{h(r_c)}{r_c} \right)$ \\
$v_{22}(r)$ &
$\frac{3}{r^3}  $ &
$\left(-\frac{g_2(r)}{r} + h_2(r) \right)$ &
$\left(-\frac{g(r)}{r}+h(r) \right)
-\left(-\frac{g(r_c)}{r_c}+h(r_c) \right) $ \\
&&&$  -(r-r_c) \left( \frac{g(r_c)}{r_c^2}-\frac{h(r_c)}{r_c}+s(r_c) \right)$ 
\\
%
%
%
%Di-Qu &
$v_{31}(r)$ &
$\frac{3}{r^4}  $ &
$\left(-\frac{g_3(r)}{r^2} + \frac{h_3(r)}{r} \right)$ &
$\left( -\frac{g(r)}{r^2}+\frac{h(r)}{r} \right)
-\left(-\frac{g(r_c)}{r_c^2}+\frac{h(r_c)}{r_c} \right) $\\
&&&$  -(r-r_c) \left(\frac{2g(r_c)}{r_c^3}-\frac{2h(r_c)}{r_c^2}+\frac{s(r_c)}{r_c} \right)$ 
\\
% 
$v_{32}(r)$ &
$-\frac{15}{r^4}  $ &
$\left( \frac{3g_3(r)}{r^2} - \frac{3h_3(r)}{r} + s_3(r) \right)$ &
$\left( \frac{3g(r)}{r^2} - \frac{3h(r)}{r} + s(r) \right)
- \left( \frac{3g(r_c)}{r_c^2} - \frac{3h(r_c)}{r_c} + s(r_c) \right)$ \\
&&&$  -(r-r_c) \left( \frac{-6g(r_c)}{r_c^3}+\frac{6h(r_c)}{r_c^2}-\frac{3s(r_c)}{r_c}+t(r_c) \right)$ 
\\
%
%
%
%Qu-Qu&
$v_{41}(r)$ &
$\frac{3}{r^5} $ &
$\left(-\frac{g_4(r)}{r^3} +\frac{h_4(r)}{r^2} \right) $  &
$\left( -\frac{g(r)}{r^3} + \frac{h(r)}{r^2} \right)
- \left( -\frac{g(r_c)}{r_c^3} + \frac{h(r_c)}{r_c^2} \right)$ \\
&&&$  -(r-r_c) \left( \frac{3g(r_c)}{r_c^4}-\frac{3h(r_c)}{r_c^3}+\frac{s(r_c)}{r_c^2} \right)$ 
\\
% 2
$v_{42}(r)$ &
$- \frac{15}{r^5}   $ &
$\left( \frac{3g_4(r)}{r^3} - \frac{3h_4(r)}{r^2}+\frac{s_4(r)}{r} \right)$ &
$\left( \frac{3g(r)}{r^3} - \frac{3h(r)}{r^2}+\frac{s(r)}{r} \right)
-\left( \frac{3g(r_c)}{r_c^3} - \frac{3h(r_c)}{r_c^2}+\frac{s(r_c)}{r_c} \right)$ \\
&&&$  -(r-r_c) \left(- \frac{9g(r_c)}{r_c^4}+\frac{9h(r_c)}{r_c^3}
-\frac{4s(r_c)}{r_c^2} + \frac{t(r_c)}{r_c}\right)$ 
\\
% 3
$v_{43}(r)$ &
$ \frac{105}{r^5}  $ &
$\left(-\frac{15g_4(r)}{r^3}+\frac{15h_4(r)}{r^2}-\frac{6s_4(r)}{r} + t_4(r)\right) $ &
$\left(-\frac{15g(r)}{r^3}+\frac{15h(r)}{r^2}-\frac{6s(r)}{r} + t(r)\right)$ \\
&&&$ -\left(-\frac{15g(r_c)}{r_c^3}+\frac{15h(r_c)}{r_c^2}-\frac{6s(r_c)}{r_c} + t(r_c)\right)$ \\
&&&$ -(r-r_c)\left(\frac{45g(r_c)}{r_c^4}-\frac{45h(r_c)}{r_c^3}+\frac{21s(r_c)}{r_c^2}
-\frac{6t(r_c)}{r_c}+u(r_c) \right)$ \\
\end{tabular}
\end{ruledtabular}
\end{table*}
%
%
% FORCE  TABLE of radial functions  ----------------------------------------------------------------------------------------------------------------
%

\begin{table}
\caption{\label{tab:tableFORCE}Radial functions used in the force equations.}
\begin{ruledtabular}
\begin{tabular}{cc}
Generic&Method 1 or Method 2
\\ \hline
%
%
%
$w_a(r)$&
$\frac{d v_{01}}{dr}$ \\
%
%
$w_b(r)$ &
$\frac{d v_{11}}{dr} - \frac{v_{11}(r)}{r} $ \\
%
$w_c(r)$ &
$\frac{v_{11}(r)}{r}$ \\
%
%
$w_d(r)$&
$\frac{d v_{21}}{dr}$ \\
%
$w_e(r)$ &
$\frac{v_{22}(r)}{r}$ \\
% 
%
$w_f(r)$&
$\frac{d v_{22}}{dr} - \frac{2v_{22}(r)}{r}$\\
%
$w_g(r)$& 
$\frac{v_{31}(r)}{r}$\\
%
$w_h(r)$ &
$\frac{d v_{31}}{dr} -\frac{v_{31}(r)}{r}$\\
% 2
$w_i(r)$ &
$\frac{v_{32}(r)}{r}$ \\
% 
$w_j(r)$ &
$\frac{d v_{32}}{dr}  - \frac{3v_{32}}{r}$ \\
%
$w_k(r)$ &
$\frac{d v_{41}}{dr} $  \\
%
$w_l(r)$ &
$\frac{d v_{42}}{dr} -\frac{2v_{42}(r)}{r}$ \\
%
$w_m(r)$ &
$\frac{d v_{43}}{dr} -\frac{4v_{43}(r)}{r}$ \\
%
$w_n(r)$ &
$\frac{v_{42}(r)}{r}$ \\
%
$w_o(r)$ &
$\frac{v_{43}(r)}{r}$ \\
%

\end{tabular}
\end{ruledtabular}
\end{table}
%
%
%

\subsection{Forces}

The force $\mathbf{F}_{\bf a}$ on $\bf{a}$ due to $\bf{b}$ is the negative of
the force  $\mathbf{F}_{\bf b}$ on $\bf{b}$ due to $\bf{a}$.  For a simple charge-charge
interaction, these forces will point along the $\pm \hat{r}$ directions, where 
$\mathbf{r}=\mathbf{r}_b - \mathbf{r}_a $.  Thus
%
\begin{equation}
F_{\bf a \alpha} = \hat{r}_\alpha \frac{\partial U_{C_{\bf a}C_{\bf b}}}{\partial r} 
\quad \text{and} \quad  F_{\bf b \alpha} 
= - \hat{r}_\alpha \frac{\partial U_{C_{\bf a}C_{\bf b}}} {\partial r}  .
\end{equation}
%
The concept of obtaining a force from an energy by taking a gradient is the same for
higher-order multipole interactions, the trick is to make sure that all
$r$-dependent derivatives are considered.
As is pointed out by Allen and Germano, this is straightforward if the
interaction energies are written recognizing explicit 
$\hat{r}$ and body axes ($\hat{a}_m$, $\hat{b}_n$) dependences:
%
\begin{equation}
U(r,\{\hat{a}_m \cdot \hat{r} \}, 
\{\hat{b}_n\cdot \hat{r} \} 
\{\hat{a}_m \cdot \hat{b}_n \}) .
\label{ugeneral}
\end{equation}
%
Then,
%
\begin{equation}
\mathbf{F}_{\bf a}=-\mathbf{F}_{\bf b} =  \frac{\partial U}{\partial \mathbf{r}} 
= \frac{\partial U}{\partial r} \hat{r} 
 + \sum_m \left[ 
\frac{\partial U}{\partial (\hat{a}_m \cdot \hat{r})} 
\frac { \partial (\hat{a}_m \cdot \hat{r})}{\partial \mathbf{r}} 
+ \frac{\partial U}{\partial (\hat{b}_m \cdot \hat{r})} 
\frac { \partial (\hat{b}_m \cdot \hat{r})}{\partial \mathbf{r}} 
\right] \label{forceequation}.
\end{equation}
%
Note our definition of $\mathbf{r}=\mathbf{r}_b - \mathbf{r}_b $ is opposite
that of Allen and Germano.  In simplifying the algebra, we also use:
%
\begin{eqnarray}
\frac { \partial (\hat{a}_m \cdot \hat{r})}{\partial \mathbf{r}} 
= \frac{1}{r} \left(  \hat{a}_m - (\hat{a}_m \cdot \hat{r})\hat{r}
\right) \\
\frac { \partial (\hat{b}_m \cdot \hat{r})}{\partial \mathbf{r}} 
= \frac{1}{r} \left(  \hat{b}_m - (\hat{b}_m \cdot \hat{r})\hat{r} 
\right) .
\end{eqnarray}
%
We list below the force equations written in terms  of space coordinates.  The
radial functions used in the two methods are listed in Table II.
%
%SPACE COORDINATES FORCE EQUTIONS
%
% **************************************************************************
% f ca cb
%
\begin{equation}
\mathbf{F}_{{\bf a}C_{\bf a}C_{\bf b}} = 
\frac{C_{\bf a} C_{\bf b}}{4\pi \epsilon_0}  w_a(r) \hat{r} 
\end{equation}
%
%
%
\begin{equation}
\mathbf{F}_{{\bf a}C_{\bf a}D_{\bf b}} = 
\frac{C_{\bf a}}{4\pi \epsilon_0} \Bigl[
 \left( \hat{r} \cdot \mathbf{D}_{\mathbf{b}} \right) 
w_b(r) \hat{r}  
+ \mathbf{D}_{\mathbf{b}} w_c(r) \Bigr]
\end{equation}
%
%
%
\begin{equation}
\mathbf{F}_{{\bf a}C_{\bf a}Q_{\bf b}} = 
\frac{C_{\bf a }}{4\pi \epsilon_0} \Bigr[
\text{Tr}\mathbf{Q}_{\bf b} w_d(r) \hat{r}
+ 2  \mathbf{Q}_{{\mathbf b}} \cdot \hat{r} w_e(r)
 + \left( \hat{r} \cdot  \mathbf{Q}_{{\mathbf b}} \cdot \hat{r} \right) w_f(r) \hat{r} \Bigr]
\end{equation}
%
%
%
\begin{equation}
\mathbf{F}_{{\bf a}D_{\bf a}C_{\bf b}} = 
-\frac{C_{\bf{b}}}{4\pi \epsilon_0} \Bigl[
\left( \hat{r} \cdot  \mathbf{D}_{\mathbf{a}} \right) w_b(r) \hat{r}
+ \mathbf{D}_{\mathbf{a}} w_c(r) \Bigr]
\end{equation}
%
%
%
\begin{equation}
\mathbf{F}_{{\bf a}D_{\bf a}D_{\bf b}} = 
\frac{1}{4\pi \epsilon_0} \Bigl[
- \mathbf{D}_{\mathbf {a}} \cdot  \mathbf{D}_{\mathbf{b}} w_d(r) \hat{r}
+ \left( \mathbf{D}_{\mathbf {a}} 
\left( \mathbf{D}_{\mathbf{b}} \cdot \hat{r} \right)
+ \mathbf{D}_{\mathbf {b}} \left( \mathbf{D}_{\mathbf{a}}  \cdot \hat{r} \right) \right) w_e(r)
% 2
 - \left( \hat{r} \cdot \mathbf{D}_{\mathbf {a}} \right) 
\left( \hat{r} \cdot \mathbf{D}_{\mathbf {b}} \right) w_f(r) \hat{r} \Bigr]
\end{equation}
%
%
%
\begin{equation}
\begin{split}
\mathbf{F}_{{\bf a}D_{\bf a}Q_{\bf b}} = 
& - \frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{b}} \mathbf{ D}_{\mathbf{a}}
+2 \mathbf{D}_{\mathbf{a}} \cdot 
\mathbf{Q}_{\mathbf{b}} \Bigr] w_g(r)
 - \frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{b}}
\left( \hat{r} \cdot  \mathbf{D}_{\mathbf{a}} \right) 
+2 ( \mathbf{D}_{\mathbf{a}} \cdot 
\mathbf{Q}_{\mathbf{b}} \cdot \hat{r}) \Bigr] w_h(r) \hat{r}  \\
% 3
& - \frac{1}{4\pi \epsilon_0} \Bigl[\mathbf{ D}_{\mathbf{a}}  (\hat{r} \cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r}) 
+2  (\hat{r} \cdot \mathbf{D}_{\mathbf{a}} ) (\hat{r} \cdot \mathbf{Q}_{{\mathbf b}} )  \Bigr]
w_i(r)
% 4
 -\frac{1}{4\pi \epsilon_0} 
(\hat{r} \cdot \mathbf{D}_{\mathbf{a}} )
(\hat{r} \cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r}) w_j(r) \hat{r}  
\end{split}
\end{equation}
%
%
\begin{equation}
\mathbf{F}_{{\bf a}Q_{\bf a}C_{\bf b}} = 
\frac{C_{\bf b }}{4\pi \epsilon_0} \Bigr[
\text{Tr}\mathbf{Q}_{\bf a} w_d(r) \hat{r}
+ 2  \mathbf{Q}_{{\mathbf a}} \cdot \hat{r} w_e(r)
 + \left( \hat{r} \cdot  \mathbf{Q}_{{\mathbf a}} \cdot \hat{r} \right) w_f(r) \hat{r} \Bigr]
\end{equation}
%
\begin{equation}
\begin{split}
\mathbf{F}_{{\bf a}Q_{\bf a}D_{\bf b}} = 
&\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{a}} \mathbf{D}_{\mathbf{b}} 
+2 \mathbf{D}_{\mathbf{b}} \cdot \mathbf{Q}_{\mathbf{a}}  \Bigr] w_g(r)
% 2
+ \frac{1}{4\pi \epsilon_0} \Bigl[ \text{Tr}\mathbf{Q}_{\mathbf{a}}
(\hat{r} \cdot  \mathbf{D}_{\mathbf{b}})
+2 (\mathbf{D}_{\mathbf{b}} \cdot 
\mathbf{Q}_{\mathbf{a}} \cdot \hat{r}) \Bigr] w_h(r) \hat{r}  \\
% 3
&+ \frac{1}{4\pi \epsilon_0} \Bigl[ \mathbf{D}_{\mathbf{b}} 
(\hat{r} \cdot \mathbf{Q}_{{\mathbf a}} \cdot \hat{r}) 
+2  (\hat{r} \cdot \mathbf{D}_{\mathbf{b}})
(\hat{r} \cdot  \mathbf{Q}_{{\mathbf a}} ) \Bigr]   w_i(r)
% 4
+\frac{1}{4\pi \epsilon_0} 
(\hat{r} \cdot \mathbf{D}_{\mathbf{b}}) 
(\hat{r} \cdot \mathbf{Q}_{{\mathbf a}}  \cdot \hat{r}) w_j(r) \hat{r} 
\end{split}
\end{equation}
%
%
%
\begin{equation}
\begin{split}
\mathbf{F}_{{\bf a}Q_{\bf a}Q_{\bf b}} = 
+\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{a}} \text{Tr}\mathbf{Q}_{\mathbf{b}} \hat{r}
+ 2 \text{Tr} ( \mathbf{Q}_{\mathbf{a}} \cdot  \mathbf{Q}_{\mathbf{b}} ) \Bigr] w_k(r) \hat{r} \\
% 2
+\frac{1}{4\pi \epsilon_0} \Bigl[
2\text{Tr}\mathbf{Q}_{\mathbf{b}}  (\hat{r} \cdot \mathbf{Q}_{\mathbf{a}} )  
+ 2\text{Tr}\mathbf{Q}_{\mathbf{a}}  (\hat{r} \cdot \mathbf{Q}_{\mathbf{b}} ) 
% 3
+4 (\mathbf{Q}_{\mathbf{a}}  \cdot  \mathbf{Q}_{\mathbf{b}} \cdot \hat{r})  
+  4(\hat{r} \cdot \mathbf{Q}_{\mathbf{a}} \cdot \mathbf{Q}_{\mathbf{b}}) \Bigr] w_n(r) \\
% 4
+ \frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{a}} (\hat{r} \cdot \mathbf{Q}_{\mathbf{b}} \cdot \hat{r}) 
+ \text{Tr}\mathbf{Q}_{\mathbf{b}}
(\hat{r} \cdot \mathbf{Q}_{\mathbf{a}}  \cdot \hat{r})  
% 5
+4 (\hat{r} \cdot \mathbf{Q}_{\mathbf{a}} \cdot  
\mathbf{Q}_{\mathbf{b}}   \cdot \hat{r}) \Bigr] w_l(r) \hat{r} \\
%
+ \frac{1}{4\pi \epsilon_0} \Bigl[
+ 2 (\hat{r} \cdot \mathbf{Q}_{\mathbf{a}} )
(\hat{r} \cdot \mathbf{Q}_{\mathbf{b}} \cdot \hat{r})
%6
+2 (\hat{r} \cdot \mathbf{Q}_{\mathbf{a}} \cdot \hat{r})
(\hat{r} \cdot \mathbf{Q}_{\mathbf{b}} ) \Bigr] w_o(r) \\
%  7
+ \frac{1}{4\pi \epsilon_0} 
(\hat{r} \cdot \mathbf{Q}_{\mathbf{a}}  \cdot \hat{r}) 
(\hat{r} \cdot \mathbf{Q}_{\mathbf{b}} \cdot \hat{r}) w_m(r) \hat{r} 
\end{split}
\end{equation}
%
%
% TORQUES SECTION -----------------------------------------------------------------------------------------
%
\subsection{Torques}

Following again Allen and Germano, when energies are written in the form
of Eq.~({\ref{ugeneral}), then torques can be expressed as:
%
\begin{eqnarray}
\mathbf{\tau}_{\bf a} =
 \sum_m 
\frac{\partial U}{\partial (\hat{a}_m \cdot \hat{r})} 
( \hat{r} \times \hat{a}_m )
-\sum_{mn}
\frac{\partial U}{\partial (\hat{a}_m \cdot \hat{b}_n)} 
(\hat{a}_m \times \hat{b}_n) \\
%
\mathbf{\tau}_{\bf b} =
 \sum_m 
\frac{\partial U}{\partial (\hat{b}_m \cdot \hat{r})} 
( \hat{r} \times \hat{b}_m)
+\sum_{mn}
\frac{\partial U}{\partial (\hat{a}_m \cdot \hat{b}_n)} 
(\hat{a}_m \times \hat{b}_n) .
\end{eqnarray}
%
%
Here we list the torque equations written in terms of space coordinates.
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf b}C_{\bf a}D_{\bf b}} = 
\frac{C_{\bf a}}{4\pi \epsilon_0}  (\hat{r} \times  \mathbf{D}_{\mathbf{b}}) v_{11}(r) 
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf b}C_{\bf a}Q_{\bf b}} = 
\frac{2C_{\bf a}}{4\pi \epsilon_0}
\hat{r} \times ( \mathbf{Q}_{{\mathbf b}} \cdot \hat{r}) v_{22}(r)
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf a}D_{\bf a}C_{\bf b}} =  
-\frac{C_{\bf b}}{4\pi \epsilon_0}  
(\hat{r} \times \mathbf{D}_{\mathbf{a}})  v_{11}(r) 
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf a}D_{\bf a}D_{\bf b}} = 
\frac{1}{4\pi \epsilon_0}  \mathbf{D}_{\mathbf {a}}  \times \mathbf{D}_{\mathbf{b}} v_{21}(r)
% 2
-\frac{1}{4\pi \epsilon_0} 
(\hat{r} \times \mathbf{D}_{\mathbf {a}} )
(\hat{r} \cdot \mathbf{D}_{\mathbf {b}} )  v_{22}(r)
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf b}D_{\bf a}D_{\bf b}} = 
-\frac{1}{4\pi \epsilon_0} \mathbf{D}_{\mathbf {a}} \times \mathbf{D}_{\mathbf{b}} v_{21}(r)
% 2
+\frac{1}{4\pi \epsilon_0} 
(\hat{r} \cdot \mathbf{D}_{\mathbf {a}} )
(\hat{r} \times \mathbf{D}_{\mathbf {b}} ) v_{22}(r)
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf a}D_{\bf a}Q_{\bf b}} = 
\frac{1}{4\pi \epsilon_0} \Bigl[
-\text{Tr}\mathbf{Q}_{\mathbf{b}}
(\hat{r} \times \mathbf{D}_{\mathbf{a}} )
+2 \mathbf{D}_{\mathbf{a}}  \times 
(\mathbf{Q}_{\mathbf{b}} \cdot \hat{r})
\Bigr] v_{31}(r)
% 3
-\frac{1}{4\pi \epsilon_0}
\ (\hat{r} \times \mathbf{D}_{\mathbf{a}} )
(\hat{r} \cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r}) v_{32}(r)
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf b}D_{\bf a}Q_{\bf b}} =
 \frac{1}{4\pi \epsilon_0} \Bigl[
+2 ( \mathbf{D}_{\mathbf{a}} \cdot \mathbf{Q}_{\mathbf{b}} ) \times
\hat{r} 
-2 \mathbf{D}_{\mathbf{a}}  \times 
(\mathbf{Q}_{\mathbf{b}} \cdot \hat{r})
\Bigr] v_{31}(r)
% 2
+\frac{2}{4\pi \epsilon_0}
(\hat{r} \cdot \mathbf{D}_{\mathbf{a}})
(\hat{r} \cdot \mathbf{Q}_{\mathbf{b}}) \times \hat{r} v_{32}(r)
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf a}Q_{\bf a}D_{\bf b}} =
\frac{1}{4\pi \epsilon_0} \Bigl[
-2 (\mathbf{D}_{\mathbf{b}}  \cdot \mathbf{Q}_{\mathbf{a}} ) \times \hat{r} 
+2 \mathbf{D}_{\mathbf{b}}  \times 
(\mathbf{Q}_{\mathbf{a}}  \cdot \hat{r})
\Bigr] v_{31}(r)
% 3
- \frac{2}{4\pi \epsilon_0}
(\hat{r} \cdot \mathbf{D}_{\mathbf{b}} )
(\hat{r} \cdot  \mathbf{Q}_{{\mathbf a}}) \times \hat{r} v_{32}(r)
\end{equation}
%
%
%
\begin{equation}
\mathbf{\tau}_{{\bf b}Q_{\bf a}D_{\bf b}} = 
\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}\mathbf{Q}_{\mathbf{a}}
(\hat{r} \times \mathbf{D}_{\mathbf{b}} )
+2 \mathbf{D}_{\mathbf{b}}  \times
( \mathbf{Q}_{\mathbf{a}} \cdot \hat{r}) \Bigr] v_{31}(r)
% 2
+\frac{1}{4\pi \epsilon_0}
(\hat{r} \times \mathbf{D}_{\mathbf{b}} )
(\hat{r} \cdot \mathbf{Q}_{{\mathbf a}} \cdot \hat{r}) v_{32}(r)
\end{equation}
%
%
%
\begin{equation}
\begin{split}
\mathbf{\tau}_{{\bf a}Q_{\bf a}Q_{\bf b}} =
&-\frac{4}{4\pi \epsilon_0} 
\mathbf{Q}_{{\mathbf a}} \times \mathbf{Q}_{{\mathbf b}}
v_{41}(r) \\
% 2
&+ \frac{1}{4\pi \epsilon_0} 
\Bigl[-2\text{Tr}\mathbf{Q}_{\mathbf{b}}
(\hat{r} \cdot \mathbf{Q}_{{\mathbf a}} ) \times \hat{r}
+4 \hat{r} \times 
( \mathbf{Q}_{{\mathbf a}} \cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r}) 
% 3
-4 (\hat{r} \cdot \mathbf{Q}_{{\mathbf a}} )\times 
( \mathbf{Q}_{{\mathbf b}} \cdot \hat{r} ) \Bigr] v_{42}(r) \\
% 4
&+ \frac{2}{4\pi \epsilon_0}
\hat{r} \times ( \mathbf{Q}_{{\mathbf a}} \cdot \hat{r})
(\hat{r} \cdot \mathbf{Q}_{{\mathbf b}} \cdot \hat{r}) v_{43}(r)
\end{split}
\end{equation}
%
%
%
\begin{equation}
\begin{split}
\mathbf{\tau}_{{\bf b}Q_{\bf a}Q_{\bf b}} =  
&\frac{4}{4\pi \epsilon_0} 
\mathbf{Q}_{{\mathbf a}} \times \mathbf{Q}_{{\mathbf b}} v_{41}(r) \\
% 2
&+ \frac{1}{4\pi \epsilon_0} \Bigl[- 2\text{Tr}\mathbf{Q}_{\mathbf{a}}
(\hat{r} \cdot \mathbf{Q}_{{\mathbf b}} ) \times \hat{r}
-4  (\hat{r} \cdot \mathbf{Q}_{{\mathbf a}} \cdot 
\mathbf{Q}_{{\mathbf b}} ) \times
\hat{r} 
+4 ( \hat{r} \cdot \mathbf{Q}_{{\mathbf a}} ) \times 
( \mathbf{Q}_{{\mathbf b}} \cdot \hat{r})
\Bigr] v_{42}(r) \\
% 4
&+ \frac{2}{4\pi \epsilon_0}
(\hat{r} \cdot \mathbf{Q}_{{\mathbf a}} \cdot \hat{r})
\hat{r} \times ( \mathbf{Q}_{{\mathbf b}} \cdot \hat{r}) v_{43}(r)
\end{split}
\end{equation}
%

\section{Comparison to known multipolar energies}

To understand how these new real-space multipole methods behave in
computer simulations, it is vital to test against established methods
for computing electrostatic interactions in periodic systems, and to
evaluate the size and sources of any errors that arise from the
real-space cutoffs. In this paper we test Taylor-shifted and
Gradient-shifted electrostatics against analytical methods for
computing the energies of ordered multipolar arrays.  In the following
paper, we test the new methods against the multipolar Ewald sum for
computing the energies, forces and torques for a wide range of typical
condensed-phase (disordered) systems.

Because long-range electrostatic effects can be significant in
crystalline materials, ordered multipolar arrays present one of the
biggest challenges for real-space cutoff methods.  The dipolar
analogues to the Madelung constants were first worked out by Sauer,
who computed the energies of ordered dipole arrays of zero
magnetization and obtained a number of these constants.\cite{Sauer}
This theory was developed more completely by Luttinger and
Tisza\cite{LT,LT2} who tabulated energy constants for the Sauer arrays and
other periodic structures.  We have repeated the Luttinger \& Tisza
series summations to much higher order and obtained the following
energy constants (converged to one part in $10^9$):
\begin{table*}
\centering{
  \caption{Luttinger \& Tisza arrays and their associated
    energy constants. Type "A" arrays have nearest neighbor strings of
    antiparallel dipoles.  Type "B" arrays have nearest neighbor
    strings of antiparallel dipoles if the dipoles are contained in a
    plane perpendicular to the dipole direction that passes through
    the dipole.}
}
\label{tab:LT}
\begin{ruledtabular}
\begin{tabular}{cccc}
Array Type &  Lattice &   Dipole Direction &    Energy constants \\ \hline
   A     &      SC       &      001         &      -2.676788684 \\
   A     &      BCC      &      001         &       0 \\
   A     &      BCC      &      111         &      -1.770078733 \\
   A     &      FCC      &      001         &       2.166932835 \\
   A     &      FCC      &      011         &      -1.083466417 \\

   *     &      BCC      &    minimum       &      -1.985920929 \\

   B     &      SC        &     001         &      -2.676788684 \\
   B     &      BCC       &     001         &      -1.338394342 \\
   B     &      BCC       &     111         &     -1.770078733 \\
   B     &      FCC       &     001         &      -1.083466417 \\
   B     &      FCC       &     011         &      -1.807573634 
\end{tabular}
\end{ruledtabular}
\end{table*}

In addition to the A and B arrays, there is an additional minimum
energy structure for the BCC lattice that was found by Luttinger \&
Tisza.  The total electrostatic energy for an array is given by:
\begin{equation}
  E = C N^2 \mu^2
\end{equation}
where $C$ is the energy constant given above, $N$ is the number of
dipoles per unit volume, and $\mu$ is the strength of the dipole.

{\it Quadrupolar} analogues to the Madelung constants were first worked out by Nagai and Nakamura who
computed the energies of selected quadrupole arrays based on
extensions to the Luttinger and Tisza
approach.\cite{Nagai01081960,Nagai01091963}  We have compared the
energy constants for the lowest energy configurations for linear
quadrupoles shown in table \ref{tab:NNQ}

\begin{table*}
\centering{
  \caption{Nagai and Nakamura Quadurpolar arrays}}
\label{tab:NNQ}
\begin{ruledtabular}
\begin{tabular}{ccc}
 Lattice &   Quadrupole Direction &    Energy constants \\ \hline
  SC       &      111         &      -8.3 \\
  BCC      &      011         &      -21.7 \\
  FCC      &      111         &      -80.5 
\end{tabular}
\end{ruledtabular}
\end{table*}

In analogy to the dipolar arrays, the total electrostatic energy for
the quadrupolar arrays is:
\begin{equation}
 E = C \frac{3}{4} N^2 Q^2
\end{equation} 
where $Q$ is the quadrupole moment.


\begin{acknowledgments}
Support for this project was provided by the National Science
Foundation under grant CHE-0848243. Computational time was provided by
the Center for Research Computing (CRC) at the University of Notre
Dame.
\end{acknowledgments}

\appendix

\section{Smith's $B_l(r)$ functions for smeared-charge distributions}

The following summarizes Smith's $B_l(r)$ functions and
includes formulas given in his appendix.  

The first function $B_0(r)$ is defined by
%
\begin{equation}
B_0(r)=\frac{\text{erfc}(\alpha r)}{r} = \frac{2}{\sqrt{\pi}r}=
\int_{\alpha r}^{\infty} \text{e}^{-s^2} ds .
\end{equation}
%
The first derivative of this function is
%
\begin{equation}
\frac{dB_0(r)}{dr}=-\frac{1}{r^2}\text{erfc}(\alpha r)
-\frac{2\alpha}{r\sqrt{\pi}}\text{e}^{-{\alpha}^2r^2}
\end{equation}
%
and can be rewritten in terms of a function $B_1(r)$:
%
\begin{equation}
B_1(r)=-\frac{1}{r}\frac{dB_0(r)}{dr}
\end{equation}
%
In general,
\begin{equation}
B_l(r)=-\frac{1}{r}\frac{dB_{l-1}(r)}{dr} 
= \frac{1}{r^2} \left[ (2l-1)B_{l-1}(r) + \frac {(2\alpha^2)^l}{\alpha \sqrt{\pi}}
\text{e}^{-{\alpha}^2r^2}
\right] .
\end{equation}
%
Using these formulas, we find
%
\begin{eqnarray}
\frac{dB_0}{dr}=-rB_1(r) \\
\frac{d^2B_0}{dr^2}=-B_1(r) + r^2B_2(r) \\
\frac{d^3B_0}{dr^3}=3rB_2(r) - r^3B_3(r) \\
\frac{d^4B_0}{dr^4}=3B_2(r) - 6r^2B_3(r)+r^4B_4(r) \\
\frac{d^5B_0}{dr^5}=-15rB_3(r) + 10r^3B_4(r) -r^5B_5(r) .
\end{eqnarray}
%
As noted by Smith,
%
\begin{equation}
B_l(r)=\frac{(2l)!}{l!2^lr^{2l+1}} - \frac {(2\alpha^2)^{l+1}}{(2l+1)\alpha \sqrt{\pi}}
+\text{O}(r) .
\end{equation}

\section{Method 1, the $r$-dependent factors}

Using the shifted damped functions $f_n(r)$ defined by:
%
\begin{equation}
f_n(r)= B_0 \Big \lvert  _r -\sum_{m=0}^{n+1} \frac {(r-r_c)^m}{m!} B_0^{(m)} \Big \lvert  _{r_c}  ,
\end{equation}
%
we first provide formulas for successive derivatives of this function.  (If there is 
no damping, then $B_0(r)$ is replaced by $1/r$, as discussed in Section~\ref{damped???}.)  First, we find:
%
\begin{equation}
\frac{\partial f_n}{\partial r_\alpha}=\hat{r}_\alpha \frac{d f_n}{d r} .
\end{equation}
%
This formula clearly brings in derivatives of Smith's $B_0(r)$ function, motivating us to
define higher-order derivatives as  follows:
%
\begin{eqnarray}
g_n(r)= \frac{d f_n}{d r} =
B_0^{(1)} \Big \lvert  _r -\sum_{m=0}^{n} \frac {(r-r_c)^m}{m!} B_0^{(m+1)} \Big \lvert  _{r_c} \\
h_n(r)= \frac{d^2f_n}{d r^2} =
B_0^{(2)} \Big \lvert  _r -\sum_{m=0}^{n-1} \frac {(r-r_c)^m}{m!} B_0^{(m+2)} \Big \lvert  _{r_c} \\
s_n(r)= \frac{d^3f_n}{d r^3} =
B_0^{(3)} \Big \lvert  _r -\sum_{m=0}^{n-2} \frac {(r-r_c)^m}{m!} B_0^{(m+3)} \Big \lvert  _{r_c} \\
t_n(r)= \frac{d^4f_n}{d r^4} =
B_0^{(4)} \Big \lvert  _r -\sum_{m=0}^{n-3} \frac {(r-r_c)^m}{m!} B_0^{(m+4)} \Big \lvert  _{r_c} \\
u_n(r)= \frac{d^5f_n}{d r^5} =
B_0^{(5)} \Big \lvert  _r -\sum_{m=0}^{n-4} \frac {(r-r_c)^m}{m!} B_0^{(m+5)} \Big \lvert  _{r_c}  .
\end{eqnarray}
%
We note that the last function needed (for quadrupole-quadrupole) is
%
\begin{equation}
u_4(r)=B_0^{(5)} \Big \lvert  _r - B_0^{(5)} \Big \lvert  _{r_c} .
\end{equation}

The functions $f_n(r)$ to $u_n(r)$ are recursively computed and stored for values of $r$
from $0$ to $r_c$.  The functions needed are listed schematically below:
%
\begin{eqnarray}
f_0 \quad f_1 \qquad \qquad \quad & \nonumber \\
g_0 \quad g_1 \quad g_2 \quad g_3 \quad &g_4 \nonumber \\
h_1 \quad h_2 \quad h_3 \quad &h_4 \nonumber \\
s_2 \quad s_3 \quad &s_4 \nonumber \\
t_3 \quad &t_4 \nonumber \\
&u_4 \nonumber .
\end{eqnarray}

Using these functions, we find
%
\begin{equation}
\frac{\partial f_n}{\partial r_\alpha} =r_\alpha \frac {g_n}{r} 
\end{equation}
%
\begin{equation}
\frac{\partial^2 f_n}{\partial r_\alpha \partial r_\beta} =\delta_{\alpha \beta}\frac {g_n}{r} 
+r_\alpha r_\beta \left( -\frac{g_n}{r^3} +\frac{h_n}{r^2}\right) 
\end{equation}
%
\begin{equation}
\frac{\partial^3 f_n}{\partial r_\alpha \partial r_\beta r_\gamma} = 
\left( \delta_{\alpha \beta} r_\gamma + \delta_{\alpha \gamma} r_\beta + 
\delta_{ \beta \gamma} r_\alpha \right)  
\left(  -\frac{g_n}{r^3} +\frac{h_n}{r^2} \right)
+ r_\alpha r_\beta r_\gamma 
\left(  \frac{3g_n}{r^5}-\frac{3h_n}{r^4} +\frac{s_n}{r^3} \right)
\end{equation}
%
\begin{eqnarray}
\frac{\partial^4 f_n}{\partial r_\alpha \partial r_\beta r_\gamma r_\delta} = 
\left( \delta_{\alpha \beta} \delta_{\gamma \delta} 
+ \delta_{\alpha \gamma} \delta_{\beta \delta}
 +\delta_{ \beta \gamma} \delta_{\alpha \delta} \right)
\left( - \frac{g_n}{r^3} + \frac{h_n}{r^2} \right)  \nonumber \\ 
+ \left( \delta_{\alpha \beta} r_\gamma r_\delta
+ \text{5 perm}
\right) \left( \frac{3 g_n}{r^5} - \frac{3h_n}{r^4} + \frac{s_n}{r^3} 
\right) \nonumber \\
+ r_\alpha r_\beta r_\gamma r_\delta
\left(  -\frac{15g_n}{r^7} + \frac{15h_n}{r^6} - \frac{6s_n}{r^5}
+ \frac{t_n}{r^4} \right)
\end{eqnarray}
%
\begin{eqnarray}
\frac{\partial^5 f_n}
{\partial r_\alpha \partial r_\beta r_\gamma r_\delta r_\epsilon} = 
\left( \delta_{\alpha \beta} \delta_{\gamma \delta} r_\epsilon
+ \text{14 perm} \right) 
\left(  \frac{3g_n}{r^5}-\frac{3h_n}{r^4} +\frac{s_n}{r^3} \right) \nonumber \\
+ \left( \delta_{\alpha \beta} r_\gamma r_\delta r_\epsilon
+ \text{9 perm}
\right) \left(- \frac{15g_n}{r^7}+\frac{15h_n}{r^7} -\frac{6s_n}{r^5} +\frac{t_n}{r^4} 
\right) \nonumber \\
+ r_\alpha r_\beta r_\gamma r_\delta r_\epsilon
\left(  \frac{105g_n}{r^9} - \frac{105h_n}{r^8} + \frac{45s_n}{r^7}
- \frac{10t_n}{r^6} +\frac{u_n}{r^5} \right)
\end{eqnarray}
%
%
%
\section{Method 2, the $r$-dependent factors}

In method 2, the kernel is not expanded, rather the individual terms in the multipole interaction energies,
see Eq. (20?).  For a smeared-charge distribution, this still brings into the algebra multiple derivatives
of the kernel $B_0(r)$.  To denote these terms, we generalize the notation of the previous appendix.
For $f(r)=1/r$ (bare Coulomb) or $f(r)=B_0(r)$ (smeared charge)
%
\begin{eqnarray}
g(r)= \frac{df}{d r}\\
h(r)= \frac{dg}{d r} = \frac{d^2f}{d r^2} \\
s(r)= \frac{dh}{d r} = \frac{d^3f}{d r^3} \\
t(r)= \frac{ds}{d r} = \frac{d^4f}{d r^4} \\
u(r)= \frac{dt}{d r} =\frac{d^5f}{d r^5} .
\end{eqnarray}
%
For $f(r)=1/r$, Table I lists these derivatives under the column ``Bare Coulomb.''  Checks of algebra can be made by using limiting forms
of equations, e.g., the leading term in the function $g_n(r)$ has $r$ dependence given by $g(r)$.  Equations (B9) to B(13)
are correct for method 2 if one just eliminates the subscript $n$.

\section{Extra Material}
%
%
%Energy in body coordinate form ---------------------------------------------------------------
%
Here are the interaction energies written in terms of the body coordinates:

%
% u ca cb
%
\begin{equation}
U_{C_{\bf a}C_{\bf b}}(r)=
\frac{C_{\bf a} C_{\bf b}}{4\pi \epsilon_0}  v_{01}(r) 
\end{equation}
%
% u ca db
%
\begin{equation}
U_{C_{\bf a}D_{\bf b}}(r)=
\frac{C_{\bf a}}{4\pi \epsilon_0} 
\sum_n (\hat{r} \cdot \hat{b}_n) D_{\mathbf{b}n} \,  v_{11}(r) 
\end{equation}
%
% u ca qb
%
\begin{equation}
U_{C_{\bf a}Q_{\bf b}}(r)=
\frac{C_{\bf a }\text{Tr}Q_{\bf b}}{4\pi \epsilon_0}  
v_{21}(r) \nonumber \\
+\frac{C_{\bf a}}{4\pi \epsilon_0}
\sum_{mn} (\hat{r} \cdot \hat{b}_m) Q_{{\mathbf b}mn} (\hat{b}_n \cdot \hat{r})
v_{22}(r) 
\end{equation}
%
% u da cb
%
\begin{equation}
U_{D_{\bf a}C_{\bf b}}(r)=
-\frac{C_{\bf b}}{4\pi \epsilon_0}  
\sum_n (\hat{r} \cdot \hat{a}_n) D_{\mathbf{a}n} \,  v_{11}(r) 
\end{equation}
%
% u da db
%
\begin{equation}
\begin{split}
% 1
U_{D_{\bf a}D_{\bf b}}(r)&=
-\frac{1}{4\pi \epsilon_0}  \sum_{mn} D_{\mathbf {a}m} 
(\hat{a}_m \cdot   \hat{b}_n)
D_{\mathbf{b}n} v_{21}(r) \\
% 2
&-\frac{1}{4\pi \epsilon_0} 
\sum_m (\hat{r} \cdot \hat{a}_m) D_{\mathbf {a}m} 
\sum_n (\hat{r} \cdot \hat{b}_n) D_{\mathbf {b}n} 
v_{22}(r)
\end{split}
\end{equation}
%
% u da qb
%
\begin{equation}
\begin{split}
% 1
U_{D_{\bf a}Q_{\bf b}}(r)&=
-\frac{1}{4\pi \epsilon_0} \left(
\text{Tr}Q_{\mathbf{b}}
\sum_n (\hat{r} \cdot \hat{a}_n) D_{\mathbf{a}n}
+2\sum_{lmn}D_{\mathbf{a}l} 
(\hat{a}_l \cdot \hat{b}_m)
Q_{\mathbf{b}mn} (\hat{b}_n \cdot \hat{r})
\right)  v_{31}(r) \\
% 2
&-\frac{1}{4\pi \epsilon_0}
\sum_l (\hat{r} \cdot \hat{a}_l) D_{\mathbf{a}l}
\sum_{mn} (\hat{r} \cdot \hat{b}_m) 
Q_{{\mathbf b}mn}
(\hat{b}_n \cdot \hat{r}) v_{32}(r)
\end{split}
\end{equation}
%
% u qa cb
%
\begin{equation}
U_{Q_{\bf a}C_{\bf b}}(r)=
\frac{C_{\bf b }\text{Tr}Q_{\bf a}}{4\pi \epsilon_0}  v_{21}(r)
+\frac{C_{\bf b}}{4\pi \epsilon_0}
\sum_{mn} (\hat{r} \cdot \hat{a}_m) Q_{{\mathbf a}mn} (\hat{a}_n \cdot \hat{r}) v_{22}(r)
\end{equation}
%
% u qa db
%
\begin{equation}
\begin{split}
%1
U_{Q_{\bf a}D_{\bf b}}(r)&=
\frac{1}{4\pi \epsilon_0} \left(
\text{Tr}Q_{\mathbf{a}}
\sum_n (\hat{r} \cdot \hat{b}_n) D_{\mathbf{b}n}
+2\sum_{lmn}D_{\mathbf{b}l} 
(\hat{b}_l \cdot \hat{a}_m)
Q_{\mathbf{a}mn} (\hat{a}_n \cdot \hat{r})
\right) v_{31}(r)  \\
% 2
&+\frac{1}{4\pi \epsilon_0}
\sum_l (\hat{r} \cdot \hat{b}_l) D_{\mathbf{b}l}
\sum_{mn} (\hat{r} \cdot \hat{a}_m) 
Q_{{\mathbf a}mn}
(\hat{a}_n \cdot \hat{r}) v_{32}(r)
\end{split}
\end{equation}
%
% u qa qb
%
\begin{equation}
\begin{split}
%1
U_{Q_{\bf a}Q_{\bf b}}(r)&=
\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}Q_{\mathbf{a}} \text{Tr}Q_{\mathbf{b}}
+2\sum_{lmnp} (\hat{a}_l \cdot \hat{b}_p) 
Q_{\mathbf{a}lm}  Q_{\mathbf{b}np} 
(\hat{a}_m \cdot \hat{b}_n) \Bigr] 
v_{41}(r) \\
% 2
&+ \frac{1}{4\pi \epsilon_0} 
\Bigl[ \text{Tr}Q_{\mathbf{a}}
\sum_{lm} (\hat{r} \cdot \hat{b}_l )
Q_{{\mathbf b}lm}
(\hat{b}_m \cdot \hat{r})
+\text{Tr}Q_{\mathbf{b}}
\sum_{lm} (\hat{r} \cdot \hat{a}_l )
Q_{{\mathbf a}lm}
(\hat{a}_m \cdot \hat{r}) \\
% 3
&+4 \sum_{lmnp}
(\hat{r} \cdot \hat{a}_l ) 
Q_{{\mathbf a}lm}
(\hat{a}_m \cdot \hat{b}_n)
Q_{{\mathbf b}np}
(\hat{b}_p \cdot \hat{r})
\Bigr] v_{42}(r)  \\
% 4
&+ \frac{1}{4\pi \epsilon_0}
\sum_{lm} (\hat{r} \cdot \hat{a}_l) 
Q_{{\mathbf a}lm}
(\hat{a}_m \cdot \hat{r})
\sum_{np}  (\hat{r} \cdot \hat{b}_n) 
Q_{{\mathbf b}np}
(\hat{b}_p \cdot \hat{r})  v_{43}(r).
\end{split}
\end{equation}
%


% BODY coordinates force equations --------------------------------------------
%
%
Here are the force equations written in terms of body coordinates.
%
% f ca cb
%
\begin{equation}
\mathbf{F}_{{\bf a}C_{\bf a}C_{\bf b}} = 
\frac{C_{\bf a} C_{\bf b}}{4\pi \epsilon_0}  w_a(r) \hat{r}
\end{equation}
%
% f ca db
%
\begin{equation}
\mathbf{F}_{{\bf a}C_{\bf a}D_{\bf b}} = 
\frac{C_{\bf a}}{4\pi \epsilon_0}  
\sum_n (\hat{r} \cdot \hat{b}_n) D_{\mathbf{b}n} w_b(r) \hat{r}
+\frac{C_{\bf a}}{4\pi \epsilon_0}  
\sum_n  D_{\mathbf{b}n} \hat{b}_n w_c(r)
\end{equation}
%
% f ca qb
%
\begin{equation}
\begin{split}
% 1
\mathbf{F}_{{\bf a}C_{\bf a}Q_{\bf b}} = 
\frac{1}{4\pi \epsilon_0}  
C_{\bf a }\text{Tr}Q_{\bf b} w_d(r) \hat{r}
+ 2C_{\bf a } \sum_l  \hat{b}_l Q_{{\mathbf b}ln} (\hat{b}_n \cdot \hat{r}) w_e(r) \\
% 2
+\frac{C_{\bf a}}{4\pi \epsilon_0}
\sum_{mn} (\hat{r} \cdot \hat{b}_m) Q_{{\mathbf b}mn} (\hat{b}_n \cdot \hat{r}) w_f(r) \hat{r} 
\end{split}
\end{equation}
%
% f da cb
%
\begin{equation}
\mathbf{F}_{{\bf a}D_{\bf a}C_{\bf b}} = 
-\frac{C_{\bf{b}}}{4\pi \epsilon_0} 
\sum_n (\hat{r} \cdot \hat{a}_n) D_{\mathbf{a}n} w_b(r)  \hat{r}
-\frac{C_{\bf{b}}}{4\pi \epsilon_0} 
\sum_n  D_{\mathbf{a}n} \hat{a}_n w_c(r)
\end{equation}
% 
% f da db
%
\begin{equation}
\begin{split}
% 1
\mathbf{F}_{{\bf a}D_{\bf a}D_{\bf b}} &= 
-\frac{1}{4\pi \epsilon_0}
 \sum_{mn} D_{\mathbf {a}m} 
(\hat{a}_m \cdot   \hat{b}_n)
D_{\mathbf{b}n}  w_d(r) \hat{r}
-\frac{1}{4\pi \epsilon_0} 
\sum_m (\hat{r} \cdot \hat{a}_m) D_{\mathbf {a}m} 
\sum_n (\hat{r} \cdot \hat{b}_n) D_{\mathbf {b}n} w_f(r) \hat{r} \\
% 2
& \quad + \frac{1}{4\pi \epsilon_0} 
\Bigl[ \sum_m D_{\mathbf {a}m} 
\hat{a}_m \sum_n D_{\mathbf{b}n} 
(\hat{b}_n \cdot \hat{r}) 
+ \sum_m D_{\mathbf {b}m} 
\hat{b}_m \sum_n D_{\mathbf{a}n} 
(\hat{a}_n \cdot \hat{r}) \Bigr] w_e(r)  \\
\end{split}
\end{equation}
%
% f da qb
%
\begin{equation}
\begin{split}
% 1
&\mathbf{F}_{{\bf a}D_{\bf a}Q_{\bf b}} = 
 - \frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}Q_{\mathbf{b}}
\sum_l  D_{\mathbf{a}l} \hat{a}_l
+2\sum_{lmn} D_{\mathbf{a}l} 
(\hat{a}_l \cdot \hat{b}_m)
Q_{\mathbf{b}mn} \hat{b}_n  \Bigr] w_g(r) \\
% 3
&  - \frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}Q_{\mathbf{b}}
\sum_n (\hat{r} \cdot \hat{a}_n) D_{\mathbf{a}n}
+2\sum_{lmn}D_{\mathbf{a}l} 
(\hat{a}_l \cdot \hat{b}_m)
Q_{\mathbf{b}mn} (\hat{b}_n \cdot \hat{r}) \Bigr] w_h(r) \hat{r} \\
% 4
&+ \frac{1}{4\pi \epsilon_0}
\Bigl[\sum_l  D_{\mathbf{a}l} \hat{a}_l
\sum_{mn} (\hat{r} \cdot \hat{b}_m) 
Q_{{\mathbf b}mn}
(\hat{b}_n \cdot \hat{r}) +2 \sum_l (\hat{r} \cdot \hat{a}_l)
 D_{\mathbf{a}l}
\sum_{mn} (\hat{r} \cdot \hat{b}_m) 
Q_{{\mathbf b}mn} \hat{b}_n \Bigr]   w_i(r)\\
% 6
&  -\frac{1}{4\pi \epsilon_0} 
\sum_l (\hat{r} \cdot \hat{a}_l) D_{\mathbf{a}l} 
\sum_{mn} (\hat{r} \cdot \hat{b}_m) 
Q_{{\mathbf b}mn}
(\hat{b}_n \cdot \hat{r})  w_j(r)  \hat{r}
\end{split}
\end{equation}
%
% force qa cb
%
\begin{equation}
\begin{split}
% 1
\mathbf{F}_{{\bf a}Q_{\bf a}C_{\bf b}} &= 
\frac{1}{4\pi \epsilon_0}  
C_{\bf b }\text{Tr}Q_{\bf a} \hat{r} w_d(r)
+ \frac{2C_{\bf b }}{4\pi \epsilon_0}  \sum_l  \hat{a}_l Q_{{\mathbf a}ln} (\hat{a}_n \cdot \hat{r}) w_e(r) \\
% 2
&  +\frac{C_{\bf b}}{4\pi \epsilon_0}
\sum_{mn} (\hat{r} \cdot \hat{a}_m) Q_{{\mathbf a}mn} (\hat{a}_n \cdot \hat{r}) w_f(r) \hat{r} 
\end{split}
\end{equation}
%
% f qa db 
%
\begin{equation}
\begin{split}
% 1
&\mathbf{F}_{{\bf a}Q_{\bf a}D_{\bf b}} = 
\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}Q_{\mathbf{a}}
\sum_l  D_{\mathbf{b}l} \hat{b}_l
+2\sum_{lmn} D_{\mathbf{b}l} 
(\hat{b}_l \cdot \hat{a}_m)
Q_{\mathbf{a}mn} \hat{a}_n  \Bigr] 
w_g(r)\\
% 3
&  + \frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}Q_{\mathbf{a}}
\sum_n (\hat{r} \cdot \hat{b}_n) D_{\mathbf{b}n} 
+2\sum_{lmn}D_{\mathbf{b}l} 
(\hat{b}_l \cdot \hat{a}_m)
Q_{\mathbf{a}mn} (\hat{a}_n \cdot \hat{r}) \Bigr] w_h(r) \hat{r} \\
% 4
&  + \frac{1}{4\pi \epsilon_0} \Bigl[ \sum_l  D_{\mathbf{b}l} \hat{b}_l
\sum_{mn} (\hat{r} \cdot \hat{a}_m) 
Q_{{\mathbf a}mn}
(\hat{a}_n \cdot \hat{r}) +2 \sum_l (\hat{r} \cdot \hat{b}_l)
 D_{\mathbf{b}l}
\sum_{mn} (\hat{r} \cdot \hat{a}_m) 
Q_{{\mathbf a}mn} \hat{a}_n \Bigr]   w_i(r) \\
% 6
&  +\frac{1}{4\pi \epsilon_0} 
\sum_l (\hat{r} \cdot \hat{b}_l) D_{\mathbf{b}l} 
\sum_{mn} (\hat{r} \cdot \hat{a}_m) 
Q_{{\mathbf a}mn}
(\hat{a}_n \cdot \hat{r})  w_j(r)  \hat{r}
\end{split}
\end{equation}
%
% f qa qb
%
\begin{equation}
\begin{split}
&\mathbf{F}_{{\bf a}Q_{\bf a}Q_{\bf b}} = 
\frac{1}{4\pi \epsilon_0} \Bigl[
\text{Tr}Q_{\mathbf{a}} \text{Tr}Q_{\mathbf{b}} 
+ 2 \sum_{lmnp} (\hat{a}_l \cdot \hat{b}_p) 
Q_{\mathbf{a}lm}  Q_{\mathbf{b}np} 
(\hat{a}_m \cdot \hat{b}_n) \Bigr] w_k(r) \hat{r}\\
&+\frac{1}{4\pi \epsilon_0} \Bigl[
2\text{Tr}Q_{\mathbf{b}} \sum_{lm} (\hat{r} \cdot \hat{a}_l) Q_{\mathbf{a}lm}  \hat{a}_m  
+ 2\text{Tr}Q_{\mathbf{a}} \sum_{lm} (\hat{r} \cdot \hat{b}_l) Q_{\mathbf{b}lm}  \hat{b}_m \\
&+ 4\sum_{lmnp} \hat{a}_l Q_{\mathbf{a}lm} (\hat{a}_m \cdot \hat{b}_n) Q_{\mathbf{b}np} (\hat{b}_p \cdot \hat{r})   
+ 4\sum_{lmnp} (\hat{r} \cdot \hat{a}_l) Q_{\mathbf{a}lm} (\hat{a}_m \cdot \hat{b}_n) Q_{\mathbf{b}np} \hat{b}_p
\Bigr] w_n(r) \\
&+ \frac{1}{4\pi \epsilon_0} 
\Bigl[ \text{Tr}Q_{\mathbf{a}}
\sum_{lm} (\hat{r} \cdot \hat{b}_l) Q_{\mathbf{b}lm} (\hat{b}_m \cdot \hat{r}) 
+ \text{Tr}Q_{\mathbf{b}}
\sum_{lm} (\hat{r} \cdot \hat{a}_l) Q_{\mathbf{a}lm}  (\hat{a}_m \cdot \hat{r}) \\
&+4\sum_{lmnp} (\hat{r} \cdot \hat{a}_l) Q_{\mathbf{a}lm} (\hat{a}_m \cdot \hat{b}_n) 
Q_{\mathbf{b}np}  (\hat{b}_p \cdot \hat{r}) \Bigr] w_l(r) \hat{r} \\
%
&+\frac{1}{4\pi \epsilon_0} \Bigl[
2\sum_{lm} (\hat{r} \cdot \hat{a}_l) Q_{\mathbf{a}lm} \hat{a}_m
\sum_{np} (\hat{r} \cdot \hat{b}_n) Q_{\mathbf{b}np} (\hat{b}_n \cdot \hat{r}) \\
&+2 \sum_{lm} (\hat{r} \cdot \hat{a}_l) Q_{\mathbf{a}lm} (\hat{a}_m \cdot \hat{r})
\sum_{np} (\hat{r} \cdot \hat{b}_n) Q_{\mathbf{b}np} \hat{b}_n \Bigr] w_o(r) \hat{r} \\
&  + \frac{1}{4\pi \epsilon_0} 
\sum_{lm} (\hat{r} \cdot \hat{a}_l) Q_{\mathbf{a}lm} (\hat{a}_m \cdot \hat{r})
\sum_{np} (\hat{r} \cdot \hat{b}_n) Q_{\mathbf{b}np} (\hat{b}_p \cdot \hat{r}) w_m(r) \hat{r} 
\end{split}
\end{equation}
%
Here we list the form of the non-zero damped shifted multipole torques showing
explicitly dependences on body axes:
%
%  t ca db
%
\begin{equation}
\mathbf{\tau}_{{\bf b}C_{\bf a}D_{\bf b}} = 
\frac{C_{\bf a}}{4\pi \epsilon_0}  
\sum_n  (\hat{r} \times \hat{b}_n)  D_{\mathbf{b}n} \,  v_{11}(r) 
\end{equation}
%
% t ca qb
%
\begin{equation}
\mathbf{\tau}_{{\bf b}C_{\bf a}Q_{\bf b}} = 
\frac{2C_{\bf a}}{4\pi \epsilon_0}
\sum_{lm} (\hat{r} \times \hat{b}_l) Q_{{\mathbf b}lm} (\hat{b}_m \cdot \hat{r}) v_{22}(r)
\end{equation}
%
%  t da cb
%
\begin{equation}
\mathbf{\tau}_{{\bf a}D_{\bf a}C_{\bf b}} = 
-\frac{C_{\bf b}}{4\pi \epsilon_0}  
\sum_n  (\hat{r} \times \hat{a}_n)  D_{\mathbf{a}n} \,  v_{11}(r) 
\end{equation}%
%
%
%  ta da db
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf a}D_{\bf a}D_{\bf b}} &= 
\frac{1}{4\pi \epsilon_0}  \sum_{mn} D_{\mathbf {a}m} 
(\hat{a}_m \times  \hat{b}_n)
D_{\mathbf{b}n} v_{21}(r) \\
% 2
&-\frac{1}{4\pi \epsilon_0} 
\sum_m (\hat{r} \times \hat{a}_m) D_{\mathbf {a}m} 
\sum_n (\hat{r} \cdot \hat{b}_n) D_{\mathbf {b}n} v_{22}(r)
\end{split}
\end{equation}
%
%  tb da db
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf b}D_{\bf a}D_{\bf b}} &= 
-\frac{1}{4\pi \epsilon_0}  \sum_{mn} D_{\mathbf {a}m} 
(\hat{a}_m \times  \hat{b}_n)
D_{\mathbf{b}n} v_{21}(r) \\
% 2
&+\frac{1}{4\pi \epsilon_0} 
\sum_m (\hat{r} \cdot \hat{a}_m) D_{\mathbf {a}m} 
\sum_n (\hat{r} \times \hat{b}_n) D_{\mathbf {b}n} v_{22}(r) 
\end{split}
\end{equation}
%
% ta da qb
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf a}D_{\bf a}Q_{\bf b}} &= 
\frac{1}{4\pi \epsilon_0} \left(
-\text{Tr}Q_{\mathbf{b}}
\sum_n (\hat{r} \times \hat{a}_n) D_{\mathbf{a}n}
+2\sum_{lmn}D_{\mathbf{a}l} 
(\hat{a}_l \times \hat{b}_m)
Q_{\mathbf{b}mn} (\hat{b}_n \cdot \hat{r})
\right) v_{31}(r)\\
% 2
&-\frac{1}{4\pi \epsilon_0}
\sum_l (\hat{r} \times \hat{a}_l) D_{\mathbf{a}l}
\sum_{mn} (\hat{r} \cdot \hat{b}_m) 
Q_{{\mathbf b}mn}
(\hat{b}_n \cdot \hat{r}) v_{32}(r)
\end{split}
\end{equation}
%
% tb da qb
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf b}D_{\bf a}Q_{\bf b}} &= 
\frac{1}{4\pi \epsilon_0} \left(
-2\sum_{lmn}D_{\mathbf{a}l} 
(\hat{a}_l \cdot \hat{b}_m)
Q_{\mathbf{b}mn} (\hat{r} \times \hat{b}_n)
-2\sum_{lmn}D_{\mathbf{a}l} 
(\hat{a}_l \times \hat{b}_m)
Q_{\mathbf{b}mn} (\hat{b}_n \cdot \hat{r})
\right) v_{31}(r) \\
% 2
&-\frac{2}{4\pi \epsilon_0}
\sum_l (\hat{r} \cdot \hat{a}_l) D_{\mathbf{a}l}
\sum_{mn} (\hat{r} \cdot \hat{b}_m) 
Q_{{\mathbf b}mn}
(\hat{r}\times \hat{b}_n) v_{32}(r)
\end{split}
\end{equation}
%
% ta qa cb
%
\begin{equation}
\mathbf{\tau}_{{\bf a}Q_{\bf a}C_{\bf b}} = 
\frac{2C_{\bf a}}{4\pi \epsilon_0}
\sum_{lm} (\hat{r} \cdot \hat{a}_l) Q_{{\mathbf a}lm} (\hat{r} \times \hat{a}_m) v_{22}(r)
\end{equation}
%
% ta qa db
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf a}Q_{\bf a}D_{\bf b}} &= 
\frac{1}{4\pi \epsilon_0} \left(
2\sum_{lmn}D_{\mathbf{b}l} 
(\hat{b}_l \cdot \hat{a}_m)
Q_{\mathbf{a}mn} (\hat{r} \times \hat{a}_n)
+2\sum_{lmn}D_{\mathbf{b}l} 
(\hat{a}_l \times \hat{b}_m)
Q_{\mathbf{a}mn} (\hat{a}_n \cdot \hat{r})
\right) v_{31}(r) \\
% 2
&+\frac{2}{4\pi \epsilon_0}
\sum_l (\hat{r} \cdot \hat{b}_l) D_{\mathbf{b}l}
\sum_{mn} (\hat{r} \cdot \hat{a}_m) 
Q_{{\mathbf a}mn}
(\hat{r}\times \hat{a}_n) v_{32}(r)
\end{split}
\end{equation}
%
% tb qa db
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf b}Q_{\bf a}D_{\bf b}} &= 
\frac{1}{4\pi \epsilon_0} \left(
\text{Tr}Q_{\mathbf{a}}
\sum_n (\hat{r} \times \hat{b}_n) D_{\mathbf{b}n}
+2\sum_{lmn}D_{\mathbf{b}l} 
(\hat{a}_l \times \hat{b}_m)
Q_{\mathbf{a}mn} (\hat{a}_n \cdot \hat{r})
\right) v_{31}(r)\\
% 2
&\frac{1}{4\pi \epsilon_0}
\sum_l (\hat{r} \times \hat{b}_l) D_{\mathbf{b}l}
\sum_{mn} (\hat{r} \cdot \hat{a}_m) 
Q_{{\mathbf a}mn}
(\hat{a}_n \cdot \hat{r}) v_{32}(r)
\end{split}
\end{equation}
%
% ta qa qb
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf a}Q_{\bf a}Q_{\bf b}} &= 
-\frac{4}{4\pi \epsilon_0} 
\sum_{lmnp} (\hat{a}_l \times \hat{b}_p)
Q_{\mathbf{a}lm}  Q_{\mathbf{b}np} 
(\hat{a}_m \cdot \hat{b}_n) v_{41}(r) \\
% 2
&+ \frac{1}{4\pi \epsilon_0} 
\Bigl[
2\text{Tr}Q_{\mathbf{b}}
\sum_{lm} (\hat{r} \cdot \hat{a}_l )
Q_{{\mathbf a}lm}
(\hat{r} \times \hat{a}_m)
+4 \sum_{lmnp}
(\hat{r} \times \hat{a}_l ) 
Q_{{\mathbf a}lm}
(\hat{a}_m \cdot \hat{b}_n)
Q_{{\mathbf b}np}
(\hat{b}_p \cdot \hat{r}) \\
% 3
&-4 \sum_{lmnp}
(\hat{r} \cdot \hat{a}_l ) 
Q_{{\mathbf a}lm}
(\hat{a}_m \times \hat{b}_n)
Q_{{\mathbf b}np}
(\hat{b}_p \cdot \hat{r})
\Bigr] v_{42}(r) \\
% 4
&+ \frac{2}{4\pi \epsilon_0}
\sum_{lm} (\hat{r} \times \hat{a}_l) 
Q_{{\mathbf a}lm}
(\hat{a}_m \cdot \hat{r})
\sum_{np}  (\hat{r} \cdot \hat{b}_n) 
Q_{{\mathbf b}np}
(\hat{b}_p \cdot \hat{r})  v_{43}(r)\\
\end{split}
\end{equation}
%
% tb qa qb
%
\begin{equation}
\begin{split}
% 1
\mathbf{\tau}_{{\bf b}Q_{\bf a}Q_{\bf b}} &= 
\frac{4}{4\pi \epsilon_0} 
\sum_{lmnp} (\hat{a}_l \cdot \hat{b}_p)
Q_{\mathbf{a}lm}  Q_{\mathbf{b}np} 
(\hat{a}_m \times \hat{b}_n) v_{41}(r) \\
% 2
&+ \frac{1}{4\pi \epsilon_0} 
\Bigl[
2\text{Tr}Q_{\mathbf{a}}
\sum_{lm} (\hat{r} \cdot \hat{b}_l )
Q_{{\mathbf b}lm}
(\hat{r} \times \hat{b}_m)
+4 \sum_{lmnp}
(\hat{r} \cdot \hat{a}_l ) 
Q_{{\mathbf a}lm}
(\hat{a}_m \cdot \hat{b}_n)
Q_{{\mathbf b}np}
(\hat{r} \times \hat{b}_p) \\
% 3
&+4 \sum_{lmnp}
(\hat{r} \cdot \hat{a}_l ) 
Q_{{\mathbf a}lm}
(\hat{a}_m \times \hat{b}_n)
Q_{{\mathbf b}np}
(\hat{b}_p \cdot \hat{r})
\Bigr] v_{42}(r)  \\
% 4
&+ \frac{2}{4\pi \epsilon_0}
\sum_{lm} (\hat{r} \cdot \hat{a}_l) 
Q_{{\mathbf a}lm}
(\hat{a}_m \cdot \hat{r})
\sum_{np}  (\hat{r} \times \hat{b}_n) 
Q_{{\mathbf b}np}
(\hat{b}_p \cdot \hat{r}) v_{43}(r). \\
\end{split}
\end{equation}
%
\begin{table*}
\caption{\label{tab:tableFORCE2}Radial functions used in the force equations.}
\begin{ruledtabular}
\begin{tabular}{ccc}
Generic&Method 1&Method 2
\\ \hline
%
%
%
$w_a(r)$&
$g_0(r)$&
$g(r)-g(r_c)$ \\
%
%
$w_b(r)$ &
$\left( -\frac{g_1(r)}{r}+h_1(r) \right)$ &
$h(r)- h(r_c) - \frac{v_{11}(r)}{r} $ \\
%
$w_c(r)$ &
$\frac{g_1(r)}{r} $ &
$\frac{v_{11}(r)}{r}$ \\
%
%
$w_d(r)$&
$\left( -\frac{g_2(r)}{r^2} + \frac{h_2(r)}{r} \right) $ &
$\left( -\frac{g(r)}{r^2} + \frac{h(r)}{r} \right)
-\left( -\frac{g(r_c)}{r_c^2} + \frac{h(r_c)}{r_c} \right) $\\
%
$w_e(r)$ &
$\left(-\frac{g_2(r)}{r^2} + \frac{h_2(r)}{r} \right)$ &
$\frac{v_{22}(r)}{r}$ \\
% 
%
$w_f(r)$&
$\left( \frac{3g_2(r)}{r^2}-\frac{3h_2(r)}{r}+s_2(r) \right)$ &
$\left( \frac{g(r)}{r^2}-\frac{h(r)}{r}+s(r) \right) - $ \\
&&$\left( \frac{g(r_c)}{r_c^2}-\frac{h(r_c)}{r_c}+s(r_c) \right)-\frac{2v_{22}(r)}{r}$\\
%
$w_g(r)$& $ \left( -\frac{g_3(r)}{r^3}+\frac{h_3(r)}{r^2} \right)$& 
$\frac{v_{31}(r)}{r}$\\
%
$w_h(r)$ &
$\left(\frac{3g_3(r)}{r^3} -\frac{3h_3(r)}{r^2} +\frac{s_3(r)}{r} \right) $  &
$\left(\frac{2g(r)}{r^3} -\frac{2h(r)}{r^2} +\frac{s(r)}{r} \right) - $\\
&&$\left(\frac{2g(r_c)}{r_c^3} -\frac{2h(r_c)}{r_c^2} +\frac{s(r_c)}{r_c} \right) $ \\
&&$-\frac{v_{31}(r)}{r}$\\
% 2
$w_i(r)$ &
$\left(\frac{3g_3(r)}{r^3} -\frac{3h_3(r)}{r^2} +\frac{s_3(r)}{r} \right) $  &
$\frac{v_{32}(r)}{r}$ \\
% 
$w_j(r)$ &
$\left(\frac{-15g_3(r)}{r^3} + \frac{15h_3(r)}{r^2} - \frac{6s_3(r)}{r} + t_3(r) \right)  $ &
$\left(\frac{-6g(r)}{r^3} +\frac{6h(r)}{r^2} -\frac{3s(r)}{r} +t(r) \right) $  \\
&&$\left(\frac{-6g(_cr)}{r_c^3} +\frac{6h(r_c)}{r_c^2} -\frac{3s(r_c)}{r_c} +t(r_c) \right) -\frac{3v_{32}}{r}$ \\
%
$w_k(r)$ &
$\left(\frac{3g_4(r)}{r^4} -\frac{3h_4(r)}{r^3} +\frac{s_4(r)}{r^2}  \right)$ &
$\left(\frac{3g(r)}{r^4} -\frac{3h(r)}{r^3} +\frac{s(r)}{r^2}  \right)$  \\
&&$\left(\frac{3g(r_c)}{r_c^4} -\frac{3h(r_c)}{r_c^3} +\frac{s(r_c)}{r_c^2}  \right)$ \\
%
$w_l(r)$ &
$\left(-\frac{15g_4(r)}{r^4} +\frac{15h_4(r)}{r^3} -\frac{6s_4(r)}{r^2} +\frac{t_4(r)}{r} \right)$ &
$\left(-\frac{9g(r)}{r^4} +\frac{9h(r)}{r^3} -\frac{4s(r)}{r^2} +\frac{t(r)}{r} \right)$ \\
&&$\left(-\frac{9g(r)}{r^4} +\frac{9h(r)}{r^3} -\frac{4s(r)}{r^2} +\frac{t(r)}{r} \right)
-\frac{2v_{42}(r)}{r}$ \\
%
$w_m(r)$ &
$\left(\frac{105g_4(r)}{r^4} - \frac{105h_4(r)}{r^3} + \frac{45s_4(r)}{r^2} - \frac{10t_4(r)}{r} +u_4(r) \right)$ &
$\left(\frac{45g(r)}{r^4} -\frac{45h(r)}{r^3} +\frac{21s(r)}{r^2} -\frac{6t(r)}{r} +u(r) \right)$ \\
&&$\left(\frac{45g(r_c)}{r_c^4} -\frac{45h(r_c)}{r_c^3} 
+\frac{21s(r_c)}{r_c^2} -\frac{6t(r_c)}{r_c} +u(r_c) \right) $ \\ 
&&$-\frac{4v_{43}(r)}{r}$ \\
%
$w_n(r)$ &
$\left(\frac{3g_4(r)}{r^4} -\frac{3h_4(r)}{r^3} +\frac{s_4(r)}{r^2}  \right)$ &
$\frac{v_{42}(r)}{r}$ \\
%
$w_o(r)$ &
$\left(-\frac{15g_4(r)}{r^4} +\frac{15h_4(r)}{r^3} -\frac{6s_4(r)}{r^2} +\frac{t_4(r)}{r} \right)$ &
$\frac{v_{43}(r)}{r}$ \\
%
\end{tabular}
\end{ruledtabular}
\end{table*}

\newpage

\bibliography{multipole}

\end{document}
%
% ****** End of file multipole.tex ******
Revision:	3980
Committed:	Fri Dec 6 18:50:14 2013 UTC (10 years, 6 months ago) by gezelter
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